( 2 x ^ { 3 } - 4 y ^ { 3 } ) ^ { 2 } = d y
Datrys ar gyfer d (complex solution)
\left\{\begin{matrix}d=\frac{4\left(x^{3}-2y^{3}\right)^{2}}{y}\text{, }&y\neq 0\\d\in \mathrm{C}\text{, }&x=0\text{ and }y=0\end{matrix}\right.
Datrys ar gyfer d
\left\{\begin{matrix}d=\frac{4\left(x^{3}-2y^{3}\right)^{2}}{y}\text{, }&y\neq 0\\d\in \mathrm{R}\text{, }&x=0\text{ and }y=0\end{matrix}\right.
Datrys ar gyfer x (complex solution)
x\in \frac{2^{\frac{2}{3}}\sqrt[3]{\sqrt{y}\left(4y^{\frac{5}{2}}+\sqrt{d}\right)}}{2},\frac{2^{\frac{2}{3}}e^{\frac{4\pi i}{3}}\sqrt[3]{\sqrt{y}\left(4y^{\frac{5}{2}}+\sqrt{d}\right)}}{2},\frac{2^{\frac{2}{3}}e^{\frac{2\pi i}{3}}\sqrt[3]{\sqrt{y}\left(4y^{\frac{5}{2}}+\sqrt{d}\right)}}{2},\frac{2^{\frac{2}{3}}e^{\frac{4\pi i}{3}}\sqrt[3]{\sqrt{y}\left(4y^{\frac{5}{2}}-\sqrt{d}\right)}}{2},\frac{2^{\frac{2}{3}}\sqrt[3]{\sqrt{y}\left(4y^{\frac{5}{2}}-\sqrt{d}\right)}}{2},\frac{2^{\frac{2}{3}}e^{\frac{2\pi i}{3}}\sqrt[3]{\sqrt{y}\left(4y^{\frac{5}{2}}-\sqrt{d}\right)}}{2}
Datrys ar gyfer x
\left\{\begin{matrix}x=\frac{2^{\frac{2}{3}}\sqrt[3]{4y^{3}-\sqrt{dy}}}{2}\text{; }x=\frac{2^{\frac{2}{3}}\sqrt[3]{4y^{3}+\sqrt{dy}}}{2}\text{, }&d\leq 0\text{ and }y\leq 0\\x=\frac{2^{\frac{2}{3}}\sqrt[6]{y}\sqrt[3]{4y^{\frac{5}{2}}-\sqrt{d}}}{2}\text{; }x=\frac{2^{\frac{2}{3}}\sqrt[6]{y}\sqrt[3]{4y^{\frac{5}{2}}+\sqrt{d}}}{2}\text{, }&y\geq 0\text{ and }d\geq 0\end{matrix}\right.
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4\left(x^{3}\right)^{2}-16x^{3}y^{3}+16\left(y^{3}\right)^{2}=dy
Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(2x^{3}-4y^{3}\right)^{2}.
4x^{6}-16x^{3}y^{3}+16\left(y^{3}\right)^{2}=dy
I godi pŵer rhif i bŵer arall, lluoswch yr esbonyddion. Lluoswch 3 a 2 i gael 6.
4x^{6}-16x^{3}y^{3}+16y^{6}=dy
I godi pŵer rhif i bŵer arall, lluoswch yr esbonyddion. Lluoswch 3 a 2 i gael 6.
dy=4x^{6}-16x^{3}y^{3}+16y^{6}
Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.
yd=4x^{6}-16x^{3}y^{3}+16y^{6}
Mae'r hafaliad yn y ffurf safonol.
\frac{yd}{y}=\frac{4\left(x^{3}-2y^{3}\right)^{2}}{y}
Rhannu’r ddwy ochr â y.
d=\frac{4\left(x^{3}-2y^{3}\right)^{2}}{y}
Mae rhannu â y yn dad-wneud lluosi â y.
4\left(x^{3}\right)^{2}-16x^{3}y^{3}+16\left(y^{3}\right)^{2}=dy
Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(2x^{3}-4y^{3}\right)^{2}.
4x^{6}-16x^{3}y^{3}+16\left(y^{3}\right)^{2}=dy
I godi pŵer rhif i bŵer arall, lluoswch yr esbonyddion. Lluoswch 3 a 2 i gael 6.
4x^{6}-16x^{3}y^{3}+16y^{6}=dy
I godi pŵer rhif i bŵer arall, lluoswch yr esbonyddion. Lluoswch 3 a 2 i gael 6.
dy=4x^{6}-16x^{3}y^{3}+16y^{6}
Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.
yd=4x^{6}-16x^{3}y^{3}+16y^{6}
Mae'r hafaliad yn y ffurf safonol.
\frac{yd}{y}=\frac{4\left(x^{3}-2y^{3}\right)^{2}}{y}
Rhannu’r ddwy ochr â y.
d=\frac{4\left(x^{3}-2y^{3}\right)^{2}}{y}
Mae rhannu â y yn dad-wneud lluosi â y.
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