Datrys (11x+3)^2-(6x+1)(6x-1)

$$( 11 x + 3 ) ^ { 2 } - ( 6 x + 1 ) ( 6 x - 1 )$$

Enrhifo

$$85x^{2}+66x+10$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(11x+3\right)^{2}.

$$121x^{2}+66x+9-\left(6x+1\right)\left(6x-1\right)$$

Ystyriwch \left(6x+1\right)\left(6x-1\right). Gellir trawsnewid lluosi yn wahaniaeth rhwng sgwariau drwy ddefnyddio’r rheol: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Sgwâr 1.

$$121x^{2}+66x+9-\left(\left(6x\right)^{2}-1\right)$$

Ehangu \left(6x\right)^{2}.

$$121x^{2}+66x+9-\left(6^{2}x^{2}-1\right)$$

Cyfrifo 6 i bŵer 2 a chael 36.

$$121x^{2}+66x+9-\left(36x^{2}-1\right)$$

I ddod o hyd i wrthwyneb 36x^{2}-1, dewch o hyd i wrthwyneb pob term.

$$121x^{2}+66x+9-36x^{2}+1$$

Cyfuno 121x^{2} a -36x^{2} i gael 85x^{2}.

$$85x^{2}+66x+9+1$$

Adio 9 a 1 i gael 10.

$$85x^{2}+66x+10$$

Ehangu

$$85x^{2}+66x+10$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(11x+3\right)^{2}.

$$121x^{2}+66x+9-\left(6x+1\right)\left(6x-1\right)$$

Ystyriwch \left(6x+1\right)\left(6x-1\right). Gellir trawsnewid lluosi yn wahaniaeth rhwng sgwariau drwy ddefnyddio’r rheol: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Sgwâr 1.

$$121x^{2}+66x+9-\left(\left(6x\right)^{2}-1\right)$$

Ehangu \left(6x\right)^{2}.

$$121x^{2}+66x+9-\left(6^{2}x^{2}-1\right)$$

Cyfrifo 6 i bŵer 2 a chael 36.

$$121x^{2}+66x+9-\left(36x^{2}-1\right)$$

I ddod o hyd i wrthwyneb 36x^{2}-1, dewch o hyd i wrthwyneb pob term.

$$121x^{2}+66x+9-36x^{2}+1$$

Cyfuno 121x^{2} a -36x^{2} i gael 85x^{2}.

$$85x^{2}+66x+9+1$$

Adio 9 a 1 i gael 10.

$$85x^{2}+66x+10$$