Datrys (2^x+1-1=1

$$( { 2 }^{ x+1 } -1 = 1$$

Datrys ar gyfer x

$$x=0$$

Camau gan Ddefnyddio Diffiniad Logarithm

Defnyddio rheolau esbonyddion a logarithmau i ddatrys yr hafaliad.

$$2^{x+1}-1=1$$

Adio 1 at ddwy ochr yr hafaliad.

$$2^{x+1}=2$$

Cymryd logarithm dwy ochr yr hafaliad.

$$\log(2^{x+1})=\log(2)$$

Logarithm rhif wedi’i godi i bŵer yw’r pŵer wedi’i lluosi â logarithm y rhif.

$$\left(x+1\right)\log(2)=\log(2)$$

Rhannu’r ddwy ochr â \log(2).

$$x+1=\frac{\log(2)}{\log(2)}$$

Gyda’r fformiwla newid-sail \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x+1=\log_{2}\left(2\right)$$

Tynnu 1 o ddwy ochr yr hafaliad.

$$x=1-1$$

Datrys ar gyfer x (complex solution)

$$x=\frac{2\pi n_{1}i}{\ln(2)}$$

$$n_{1}\in \mathrm{Z}$$