Datrys (sqrt{10}-sqrt{2})^2

$$( \sqrt { 10 } - \sqrt { 2 } ) ^ { 2 }$$

Enrhifo

$$12-4\sqrt{5}\approx 3.05572809$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(\sqrt{10}-\sqrt{2}\right)^{2}.

$$\left(\sqrt{10}\right)^{2}-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Sgwâr \sqrt{10} yw 10.

$$10-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Ffactora 10=2\times 5. Ailysgrifennu ail isradd y lluoswm \sqrt{2\times 5} fel lluoswm ail israddau \sqrt{2}\sqrt{5}.

$$10-2\sqrt{2}\sqrt{5}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Lluosi \sqrt{2} a \sqrt{2} i gael 2.

$$10-2\times 2\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Lluosi -2 a 2 i gael -4.

$$10-4\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Sgwâr \sqrt{2} yw 2.

$$10-4\sqrt{5}+2$$

Adio 10 a 2 i gael 12.

$$12-4\sqrt{5}$$

Ehangu

$$12-4\sqrt{5}$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(\sqrt{10}-\sqrt{2}\right)^{2}.

$$\left(\sqrt{10}\right)^{2}-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Sgwâr \sqrt{10} yw 10.

$$10-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Ffactora 10=2\times 5. Ailysgrifennu ail isradd y lluoswm \sqrt{2\times 5} fel lluoswm ail israddau \sqrt{2}\sqrt{5}.

$$10-2\sqrt{2}\sqrt{5}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Lluosi \sqrt{2} a \sqrt{2} i gael 2.

$$10-2\times 2\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Lluosi -2 a 2 i gael -4.

$$10-4\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Sgwâr \sqrt{2} yw 2.

$$10-4\sqrt{5}+2$$

Adio 10 a 2 i gael 12.

$$12-4\sqrt{5}$$