Datrys (log4+2)^2-(log4+4)*log4=

$$( \log 4 + 2 ) ^ { 2 } - ( \log 4 + 4 ) \cdot \log 4 =$$

Enrhifo

$$4$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(\log_{10}\left(4\right)+2\right)^{2}.

$$\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)+4-\left(\log_{10}\left(4\right)+4\right)\log_{10}\left(4\right)$$

Defnyddio’r briodwedd ddosbarthu i luosi \log_{10}\left(4\right)+4 â \log_{10}\left(4\right).

$$\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)+4-\left(\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)\right)$$

I ddod o hyd i wrthwyneb \left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right), dewch o hyd i wrthwyneb pob term.

$$\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)+4-\left(\log_{10}\left(4\right)\right)^{2}-4\log_{10}\left(4\right)$$

Cyfuno \left(\log_{10}\left(4\right)\right)^{2} a -\left(\log_{10}\left(4\right)\right)^{2} i gael 0.

$$4\log_{10}\left(4\right)+4-4\log_{10}\left(4\right)$$

Cyfuno 4\log_{10}\left(4\right) a -4\log_{10}\left(4\right) i gael 0.

$$4$$

Ffactor

$$2^{2}$$