Datrys (1/25)quad=5^x+5

$$( \frac { 1 } { 25 } ) \quad = 5 ^ { x + 5 }$$

Datrys ar gyfer x

$$x=-7$$

Camau gan Ddefnyddio Diffiniad Logarithm

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$5^{x+5}=\frac{1}{25}$$

Cymryd logarithm dwy ochr yr hafaliad.

$$\log(5^{x+5})=\log(\frac{1}{25})$$

Logarithm rhif wedi’i godi i bŵer yw’r pŵer wedi’i lluosi â logarithm y rhif.

$$\left(x+5\right)\log(5)=\log(\frac{1}{25})$$

Rhannu’r ddwy ochr â \log(5).

$$x+5=\frac{\log(\frac{1}{25})}{\log(5)}$$

Gyda’r fformiwla newid-sail \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x+5=\log_{5}\left(\frac{1}{25}\right)$$

Tynnu 5 o ddwy ochr yr hafaliad.

$$x=-2-5$$

Datrys ar gyfer x (complex solution)

$$x=\frac{i\times 2\pi n_{1}}{\ln(5)}-7$$

$$n_{1}\in \mathrm{Z}$$