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Problemau tebyg o chwiliad gwe

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\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right)+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(\frac{1}{2}x-1\right)^{2}.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x\right)^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Ystyriwch \left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right). Gellir trawsnewid lluosi yn wahaniaeth rhwng sgwariau drwy ddefnyddio’r rheol: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Sgwâr 1.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}\right)^{2}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Ehangu \left(\frac{1}{2}x\right)^{2}.
\frac{1}{4}x^{2}-x+1+\frac{1}{4}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Cyfrifo \frac{1}{2} i bŵer 2 a chael \frac{1}{4}.
\frac{1}{2}x^{2}-x+1-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Cyfuno \frac{1}{4}x^{2} a \frac{1}{4}x^{2} i gael \frac{1}{2}x^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Tynnu 1 o 1 i gael 0.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x\right)^{2}-1
Ystyriwch \left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right). Gellir trawsnewid lluosi yn wahaniaeth rhwng sgwariau drwy ddefnyddio’r rheol: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Sgwâr 1.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}\right)^{2}x^{2}-1
Ehangu \left(-\frac{1}{2}x\right)^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\frac{1}{4}x^{2}-1
Cyfrifo -\frac{1}{2} i bŵer 2 a chael \frac{1}{4}.
\frac{3}{4}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}-1
Cyfuno \frac{1}{2}x^{2} a \frac{1}{4}x^{2} i gael \frac{3}{4}x^{2}.
\frac{3}{4}x^{2}-x+\frac{1}{4}x^{2}+x+1-1
Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(\frac{1}{2}x+1\right)^{2}.
x^{2}-x+x+1-1
Cyfuno \frac{3}{4}x^{2} a \frac{1}{4}x^{2} i gael x^{2}.
x^{2}+1-1
Cyfuno -x a x i gael 0.
x^{2}
Tynnu 1 o 1 i gael 0.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right)+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(\frac{1}{2}x-1\right)^{2}.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x\right)^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Ystyriwch \left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right). Gellir trawsnewid lluosi yn wahaniaeth rhwng sgwariau drwy ddefnyddio’r rheol: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Sgwâr 1.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}\right)^{2}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Ehangu \left(\frac{1}{2}x\right)^{2}.
\frac{1}{4}x^{2}-x+1+\frac{1}{4}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Cyfrifo \frac{1}{2} i bŵer 2 a chael \frac{1}{4}.
\frac{1}{2}x^{2}-x+1-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Cyfuno \frac{1}{4}x^{2} a \frac{1}{4}x^{2} i gael \frac{1}{2}x^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Tynnu 1 o 1 i gael 0.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x\right)^{2}-1
Ystyriwch \left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right). Gellir trawsnewid lluosi yn wahaniaeth rhwng sgwariau drwy ddefnyddio’r rheol: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Sgwâr 1.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}\right)^{2}x^{2}-1
Ehangu \left(-\frac{1}{2}x\right)^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\frac{1}{4}x^{2}-1
Cyfrifo -\frac{1}{2} i bŵer 2 a chael \frac{1}{4}.
\frac{3}{4}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}-1
Cyfuno \frac{1}{2}x^{2} a \frac{1}{4}x^{2} i gael \frac{3}{4}x^{2}.
\frac{3}{4}x^{2}-x+\frac{1}{4}x^{2}+x+1-1
Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(\frac{1}{2}x+1\right)^{2}.
x^{2}-x+x+1-1
Cyfuno \frac{3}{4}x^{2} a \frac{1}{4}x^{2} i gael x^{2}.
x^{2}+1-1
Cyfuno -x a x i gael 0.
x^{2}
Tynnu 1 o 1 i gael 0.