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Problemau tebyg o chwiliad gwe

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\frac{1}{4}\left(\sqrt{3}\right)^{2}-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(\frac{1}{2}\sqrt{3}-4\sqrt{5}\right)^{2}.
\frac{1}{4}\times 3-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
Sgwâr \sqrt{3} yw 3.
\frac{3}{4}-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
Lluosi \frac{1}{4} a 3 i gael \frac{3}{4}.
\frac{3}{4}-4\sqrt{15}+16\left(\sqrt{5}\right)^{2}
I luosi \sqrt{3} a \sqrt{5}, dylid lluosi'r rhifau dan yr ail isradd.
\frac{3}{4}-4\sqrt{15}+16\times 5
Sgwâr \sqrt{5} yw 5.
\frac{3}{4}-4\sqrt{15}+80
Lluosi 16 a 5 i gael 80.
\frac{323}{4}-4\sqrt{15}
Adio \frac{3}{4} a 80 i gael \frac{323}{4}.
\frac{1}{4}\left(\sqrt{3}\right)^{2}-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(\frac{1}{2}\sqrt{3}-4\sqrt{5}\right)^{2}.
\frac{1}{4}\times 3-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
Sgwâr \sqrt{3} yw 3.
\frac{3}{4}-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
Lluosi \frac{1}{4} a 3 i gael \frac{3}{4}.
\frac{3}{4}-4\sqrt{15}+16\left(\sqrt{5}\right)^{2}
I luosi \sqrt{3} a \sqrt{5}, dylid lluosi'r rhifau dan yr ail isradd.
\frac{3}{4}-4\sqrt{15}+16\times 5
Sgwâr \sqrt{5} yw 5.
\frac{3}{4}-4\sqrt{15}+80
Lluosi 16 a 5 i gael 80.
\frac{323}{4}-4\sqrt{15}
Adio \frac{3}{4} a 80 i gael \frac{323}{4}.