Datrys (+mathfrak{F}(2+1)(2^{2}+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1

$$( + \mathfrak { F } ( 2 + 1 ) ( 2 ^ { 2 } + 1 ) ( 2 ^ { 4 } + 1 ) ( 2 ^ { 8 } + 1 ) ( 2 ^ { 16 } + 1 ) ( 2 ^ { 32 } + 1 ) + 1$$

Enrhifo

$$18446744073709551615F+1$$

Camau Ateb

Adio 2 a 1 i gael 3.

$$F\times 3\left(2^{2}+1\right)\left(2^{4}+1\right)\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1$$

Cyfrifo 2 i bŵer 2 a chael 4.

$$F\times 3\left(4+1\right)\left(2^{4}+1\right)\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1$$

Adio 4 a 1 i gael 5.

$$F\times 3\times 5\left(2^{4}+1\right)\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1$$

Lluosi 3 a 5 i gael 15.

$$F\times 15\left(2^{4}+1\right)\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1$$

Cyfrifo 2 i bŵer 4 a chael 16.

$$F\times 15\left(16+1\right)\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1$$

Adio 16 a 1 i gael 17.

$$F\times 15\times 17\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1$$

Lluosi 15 a 17 i gael 255.

$$F\times 255\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1$$

Cyfrifo 2 i bŵer 8 a chael 256.

$$F\times 255\left(256+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1$$

Adio 256 a 1 i gael 257.

$$F\times 255\times 257\left(2^{16}+1\right)\left(2^{32}+1\right)+1$$

Lluosi 255 a 257 i gael 65535.

$$F\times 65535\left(2^{16}+1\right)\left(2^{32}+1\right)+1$$

Cyfrifo 2 i bŵer 16 a chael 65536.

$$F\times 65535\left(65536+1\right)\left(2^{32}+1\right)+1$$

Adio 65536 a 1 i gael 65537.

$$F\times 65535\times 65537\left(2^{32}+1\right)+1$$

Lluosi 65535 a 65537 i gael 4294967295.

$$F\times 4294967295\left(2^{32}+1\right)+1$$

Cyfrifo 2 i bŵer 32 a chael 4294967296.

$$F\times 4294967295\left(4294967296+1\right)+1$$

Adio 4294967296 a 1 i gael 4294967297.

$$F\times 4294967295\times 4294967297+1$$

Lluosi 4294967295 a 4294967297 i gael 18446744073709551615.

$$F\times 18446744073709551615+1$$

Gwahaniaethu w.r.t. F

$$18446744073709551615$$

Camau gan Ddefnyddio Rheol Deilliadol ar gyfer Swm

Adio 2 a 1 i gael 3.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 3\left(2^{2}+1\right)\left(2^{4}+1\right)\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1)$$

Cyfrifo 2 i bŵer 2 a chael 4.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 3\left(4+1\right)\left(2^{4}+1\right)\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1)$$

Adio 4 a 1 i gael 5.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 3\times 5\left(2^{4}+1\right)\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1)$$

Lluosi 3 a 5 i gael 15.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 15\left(2^{4}+1\right)\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1)$$

Cyfrifo 2 i bŵer 4 a chael 16.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 15\left(16+1\right)\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1)$$

Adio 16 a 1 i gael 17.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 15\times 17\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1)$$

Lluosi 15 a 17 i gael 255.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 255\left(2^{8}+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1)$$

Cyfrifo 2 i bŵer 8 a chael 256.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 255\left(256+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)+1)$$

Adio 256 a 1 i gael 257.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 255\times 257\left(2^{16}+1\right)\left(2^{32}+1\right)+1)$$

Lluosi 255 a 257 i gael 65535.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 65535\left(2^{16}+1\right)\left(2^{32}+1\right)+1)$$

Cyfrifo 2 i bŵer 16 a chael 65536.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 65535\left(65536+1\right)\left(2^{32}+1\right)+1)$$

Adio 65536 a 1 i gael 65537.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 65535\times 65537\left(2^{32}+1\right)+1)$$

Lluosi 65535 a 65537 i gael 4294967295.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 4294967295\left(2^{32}+1\right)+1)$$

Cyfrifo 2 i bŵer 32 a chael 4294967296.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 4294967295\left(4294967296+1\right)+1)$$

Adio 4294967296 a 1 i gael 4294967297.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 4294967295\times 4294967297+1)$$

Lluosi 4294967295 a 4294967297 i gael 18446744073709551615.

$$\frac{\mathrm{d}}{\mathrm{d}F}(F\times 18446744073709551615+1)$$

Deilliad polynomaial yw swm deilliadau ei dermau. Deilliad term cyson yw 0. Y deilliad o ax^{n} yw nax^{n-1}.

$$18446744073709551615F^{1-1}$$

Tynnu 1 o 1.

$$18446744073709551615F^{0}$$

Ar gyfer unrhyw derm t ac eithrio 0, t^{0}=1.

$$18446744073709551615\times 1$$

Ar gyfer unrhyw derm t, t\times 1=t a 1t=t.

$$18446744073709551615$$