Datrys 391^12=2^x

$${ 391 }^{ 12 } = { 2 }^{ x }$$

Datrys ar gyfer x

$$x=12\log_{2}\left(391\right)\approx 103.332297568$$

Camau gan Ddefnyddio Diffiniad Logarithm

Cyfrifo 391 i bŵer 12 a chael 12767947514633659874603497973281.

$$12767947514633659874603497973281=2^{x}$$

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$2^{x}=12767947514633659874603497973281$$

Cymryd logarithm dwy ochr yr hafaliad.

$$\log(2^{x})=\log(12767947514633659874603497973281)$$

Logarithm rhif wedi’i godi i bŵer yw’r pŵer wedi’i lluosi â logarithm y rhif.

$$x\log(2)=\log(12767947514633659874603497973281)$$

Rhannu’r ddwy ochr â \log(2).

$$x=\frac{\log(12767947514633659874603497973281)}{\log(2)}$$

Gyda’r fformiwla newid-sail \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{2}\left(12767947514633659874603497973281\right)$$

Datrys ar gyfer x (complex solution)

$$x=\frac{2\pi n_{1}i}{\ln(2)}+12\log_{2}\left(391\right)$$

$$n_{1}\in \mathrm{Z}$$