Datrys 2^x+3=1/8

$${ 2 }^{ x+3 } = \frac{ 1 }{ 8 }$$

Datrys ar gyfer x

$$x=-6$$

Camau gan Ddefnyddio Diffiniad Logarithm

Defnyddio rheolau esbonyddion a logarithmau i ddatrys yr hafaliad.

$$2^{x+3}=\frac{1}{8}$$

Cymryd logarithm dwy ochr yr hafaliad.

$$\log(2^{x+3})=\log(\frac{1}{8})$$

Logarithm rhif wedi’i godi i bŵer yw’r pŵer wedi’i lluosi â logarithm y rhif.

$$\left(x+3\right)\log(2)=\log(\frac{1}{8})$$

Rhannu’r ddwy ochr â \log(2).

$$x+3=\frac{\log(\frac{1}{8})}{\log(2)}$$

Gyda’r fformiwla newid-sail \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x+3=\log_{2}\left(\frac{1}{8}\right)$$

Tynnu 3 o ddwy ochr yr hafaliad.

$$x=-3-3$$

Datrys ar gyfer x (complex solution)

$$x=\frac{i\times 2\pi n_{1}}{\ln(2)}-6$$

$$n_{1}\in \mathrm{Z}$$