Datrys left(t-4right)^2=left(t+4right)^2+32

$${ \left(t-4 \right) }^{ 2 } = { \left(t+4 \right) }^{ 2 } +32$$

Datrys ar gyfer t

$$t=-2$$

Camau ar gyfer Datrys Hafaliad Llinol

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(t-4\right)^{2}.

$$t^{2}-8t+16=\left(t+4\right)^{2}+32$$

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(t+4\right)^{2}.

$$t^{2}-8t+16=t^{2}+8t+16+32$$

Adio 16 a 32 i gael 48.

$$t^{2}-8t+16=t^{2}+8t+48$$

Tynnu t^{2} o'r ddwy ochr.

$$t^{2}-8t+16-t^{2}=8t+48$$

Cyfuno t^{2} a -t^{2} i gael 0.

$$-8t+16=8t+48$$

Tynnu 8t o'r ddwy ochr.

$$-8t+16-8t=48$$

Cyfuno -8t a -8t i gael -16t.

$$-16t+16=48$$

Tynnu 16 o'r ddwy ochr.

$$-16t=48-16$$

Tynnu 16 o 48 i gael 32.

$$-16t=32$$

Rhannu’r ddwy ochr â -16.

$$t=\frac{32}{-16}$$

Rhannu 32 â -16 i gael -2.

$$t=-2$$