Datrys sqrt{-2^2}=left|-1right|+1/9*-3^2+sqrt[3]{-8}

$$\sqrt{ { -2 }^{ 2 } } = \left| -1 \right| + \frac{ 1 }{ 9 } \times { -3 }^{ 2 } + \sqrt[ 3 ]{ -8 }$$

Gwireddu

Camau Ateb

Cyfrifo -2 i bŵer 2 a chael 4.

$$\sqrt{4}=|-1|+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Cyfrifo ail isradd 4 a chael 2.

$$2=|-1|+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Gwerth absoliwt rhif real a yw a pan a\geq 0, neu -a pan a<0. Gwerth absoliwt -1 yw 1.

$$2=1+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Cyfrifo -3 i bŵer 2 a chael 9.

$$2=1+\frac{1}{9}\times 9+\sqrt[3]{-8}$$

Lluosi \frac{1}{9} a 9 i gael 1.

$$2=1+1+\sqrt[3]{-8}$$

Adio 1 a 1 i gael 2.

$$2=2+\sqrt[3]{-8}$$

Cyfrifo \sqrt[3]{-8} a chael -2.

$$2=2-2$$

Tynnu 2 o 2 i gael 0.

$$2=0$$

Cymharu 2 gyda 0.

$$\text{false}$$