Datrys sqrt{m+1}+(n-3)^2=0

$$\sqrt { m + 1 } + ( n - 3 ) ^ { 2 } = 0$$

Datrys ar gyfer m

$$m=-1$$

$$n=3$$

Camau ar gyfer Datrys Hafaliadau Radical

Tynnu \left(n-3\right)^{2} o ddwy ochr yr hafaliad.

$$\sqrt{m+1}+\left(n-3\right)^{2}-\left(n-3\right)^{2}=-\left(n-3\right)^{2}$$

Mae tynnu \left(n-3\right)^{2} o’i hun yn gadael 0.

$$\sqrt{m+1}=-\left(n-3\right)^{2}$$

Sgwariwch ddwy ochr yr hafaliad.

$$m+1=\left(n-3\right)^{4}$$

Tynnu 1 o ddwy ochr yr hafaliad.

$$m+1-1=\left(n-3\right)^{4}-1$$

Mae tynnu 1 o’i hun yn gadael 0.

$$m=\left(n-3\right)^{4}-1$$

Tynnu 1 o \left(n-3\right)^{4}.

$$m=\left(n-4\right)\left(n-2\right)\left(\left(n-3\right)^{2}+1\right)$$

Datrys ar gyfer n

$$n=3$$

$$m=-1$$