Datrys sqrt{[(13)^{2}-(07)^{2}+32]^2:11^2*5+[(28)^2-023]*10^2}

$$\sqrt { [ ( 13 ) ^ { 2 } - ( 07 ) ^ { 2 } + 32 ] ^ { 2 } : 11 ^ { 2 } \cdot 5 + [ ( 28 ) ^ { 2 } - 023 ] \cdot 10 ^ { 2 } }$$

Enrhifo

$$\frac{\sqrt{9688405}}{11}\approx 282.965479891$$

Camau Ateb

Cyfrifo 13 i bŵer 2 a chael 169.

$$\sqrt{\frac{\left(169-\left(0\times 7\right)^{2}+32\right)^{2}}{11^{2}}\times 5+\left(28^{2}-0\times 23\right)\times 10^{2}}$$

Lluosi 0 a 7 i gael 0.

$$\sqrt{\frac{\left(169-0^{2}+32\right)^{2}}{11^{2}}\times 5+\left(28^{2}-0\times 23\right)\times 10^{2}}$$

Cyfrifo 0 i bŵer 2 a chael 0.

$$\sqrt{\frac{\left(169-0+32\right)^{2}}{11^{2}}\times 5+\left(28^{2}-0\times 23\right)\times 10^{2}}$$

Tynnu 0 o 169 i gael 169.

$$\sqrt{\frac{\left(169+32\right)^{2}}{11^{2}}\times 5+\left(28^{2}-0\times 23\right)\times 10^{2}}$$

Adio 169 a 32 i gael 201.

$$\sqrt{\frac{201^{2}}{11^{2}}\times 5+\left(28^{2}-0\times 23\right)\times 10^{2}}$$

Cyfrifo 201 i bŵer 2 a chael 40401.

$$\sqrt{\frac{40401}{11^{2}}\times 5+\left(28^{2}-0\times 23\right)\times 10^{2}}$$

Cyfrifo 11 i bŵer 2 a chael 121.

$$\sqrt{\frac{40401}{121}\times 5+\left(28^{2}-0\times 23\right)\times 10^{2}}$$

Lluosi \frac{40401}{121} a 5 i gael \frac{202005}{121}.

$$\sqrt{\frac{202005}{121}+\left(28^{2}-0\times 23\right)\times 10^{2}}$$

Cyfrifo 28 i bŵer 2 a chael 784.

$$\sqrt{\frac{202005}{121}+\left(784-0\times 23\right)\times 10^{2}}$$

Lluosi 0 a 23 i gael 0.

$$\sqrt{\frac{202005}{121}+\left(784-0\right)\times 10^{2}}$$

Tynnu 0 o 784 i gael 784.

$$\sqrt{\frac{202005}{121}+784\times 10^{2}}$$

Cyfrifo 10 i bŵer 2 a chael 100.

$$\sqrt{\frac{202005}{121}+784\times 100}$$

Lluosi 784 a 100 i gael 78400.

$$\sqrt{\frac{202005}{121}+78400}$$

Adio \frac{202005}{121} a 78400 i gael \frac{9688405}{121}.

$$\sqrt{\frac{9688405}{121}}$$

Ailysgrifennu ail isradd y rhaniad \sqrt{\frac{9688405}{121}} fel rhaniad ail israddau \frac{\sqrt{9688405}}{\sqrt{121}}.

$$\frac{\sqrt{9688405}}{\sqrt{121}}$$

Cyfrifo ail isradd 121 a chael 11.

$$\frac{\sqrt{9688405}}{11}$$