Datrys {l}{50{(x/2)}=795}{y=5{(x)}+2{(3x)}+2x+0}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 50 {(\frac{x}{2})} = 795 }\\ { y = 5 {(x)} + 2 {(3 x)} + 2 x + 0 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Datrys ar gyfer x, y, z, a, b, c

$$c = \frac{2067}{5} = 413\frac{2}{5} = 413.4$$

Camau Ateb

Ystyriwch yr hafaliad cyntaf. Rhannu’r ddwy ochr â 50.

$$\frac{x}{2}=\frac{795}{50}$$

Lleihau'r ffracsiwn \frac{795}{50} i'r graddau lleiaf posib drwy dynnu a chanslo allan 5.

$$\frac{x}{2}=\frac{159}{10}$$

Lluosi’r ddwy ochr â 2.

$$x=\frac{159}{10}\times 2$$

Lluosi \frac{159}{10} a 2 i gael \frac{159}{5}.

$$x=\frac{159}{5}$$

Ystyriwch yr ail hafaliad. Mewnosod y gwerthoedd sy’n hysbys i’r hafaliad.

$$y=5\times \frac{159}{5}+2\times 3\times \frac{159}{5}+2\times \frac{159}{5}+0$$

Lluosi 5 a \frac{159}{5} i gael 159.

$$y=159+2\times 3\times \frac{159}{5}+2\times \frac{159}{5}+0$$

Lluosi 2 a 3 i gael 6.

$$y=159+6\times \frac{159}{5}+2\times \frac{159}{5}+0$$

Lluosi 6 a \frac{159}{5} i gael \frac{954}{5}.

$$y=159+\frac{954}{5}+2\times \frac{159}{5}+0$$

Adio 159 a \frac{954}{5} i gael \frac{1749}{5}.

$$y=\frac{1749}{5}+2\times \frac{159}{5}+0$$

Lluosi 2 a \frac{159}{5} i gael \frac{318}{5}.

$$y=\frac{1749}{5}+\frac{318}{5}+0$$

Adio \frac{1749}{5} a \frac{318}{5} i gael \frac{2067}{5}.

$$y=\frac{2067}{5}+0$$

Adio \frac{2067}{5} a 0 i gael \frac{2067}{5}.

$$y=\frac{2067}{5}$$

Ystyriwch y trydydd hafaliad. Mewnosod y gwerthoedd sy’n hysbys i’r hafaliad.

$$z=\frac{2067}{5}$$

Ystyriwch y pedwaredd hafaliad. Mewnosod y gwerthoedd sy’n hysbys i’r hafaliad.

$$a=\frac{2067}{5}$$

Ystyriwch y pumed hafaliad. Mewnosod y gwerthoedd sy’n hysbys i’r hafaliad.

$$b=\frac{2067}{5}$$

Ystyriwch yr hafaliad (6). Mewnosod y gwerthoedd sy’n hysbys i’r hafaliad.

$$c=\frac{2067}{5}$$

Mae’r system wedi’i datrys nawr.

$$x=\frac{159}{5} y=\frac{2067}{5} z=\frac{2067}{5} a=\frac{2067}{5} b=\frac{2067}{5} c=\frac{2067}{5}$$