Datrys ∫ (from - 2 to 2) of (4x-x^3)^2 wrt x

$$\int _ { - 2 } ^ { 2 } ( 4 x - x ^ { 3 } ) ^ { 2 } d x$$

Enrhifo

$$\frac{2048}{105}\approx 19.504761905$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(4x-x^{3}\right)^{2}.

$$\int _{-2}^{2}16x^{2}-8xx^{3}+\left(x^{3}\right)^{2}\mathrm{d}x$$

Er mwyn lluosi pwerau sy’n rhannu’r un sail, adiwch eu esbonyddion. Adiwch 1 a 3 i gael 4.

$$\int _{-2}^{2}16x^{2}-8x^{4}+\left(x^{3}\right)^{2}\mathrm{d}x$$

I godi pŵer rhif i bŵer arall, lluoswch yr esbonyddion. Lluoswch 3 a 2 i gael 6.

$$\int _{-2}^{2}16x^{2}-8x^{4}+x^{6}\mathrm{d}x$$

Gwerthuso’r integryn amhenodol yn gyntaf.

$$\int 16x^{2}-8x^{4}+x^{6}\mathrm{d}x$$

Integreiddio'r swm fesul term.

$$\int 16x^{2}\mathrm{d}x+\int -8x^{4}\mathrm{d}x+\int x^{6}\mathrm{d}x$$

Ffactoreiddio allan y cysonyn ym mhob un o'r termau.

$$16\int x^{2}\mathrm{d}x-8\int x^{4}\mathrm{d}x+\int x^{6}\mathrm{d}x$$

Ers \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} ar gyfer k\neq -1, disodli \int x^{2}\mathrm{d}x gyda \frac{x^{3}}{3}. Lluoswch 16 â \frac{x^{3}}{3}.

$$\frac{16x^{3}}{3}-8\int x^{4}\mathrm{d}x+\int x^{6}\mathrm{d}x$$

Ers \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} ar gyfer k\neq -1, disodli \int x^{4}\mathrm{d}x gyda \frac{x^{5}}{5}. Lluoswch -8 â \frac{x^{5}}{5}.

$$\frac{16x^{3}}{3}-\frac{8x^{5}}{5}+\int x^{6}\mathrm{d}x$$

Ers \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} ar gyfer k\neq -1, disodli \int x^{6}\mathrm{d}x gyda \frac{x^{7}}{7}.

$$\frac{16x^{3}}{3}-\frac{8x^{5}}{5}+\frac{x^{7}}{7}$$

Symleiddio.

$$\frac{x^{7}}{7}-\frac{8x^{5}}{5}+\frac{16x^{3}}{3}$$

Yr integryn pendant yw integryn amhendant y mynegiant wedi’i werthuso ar lefel uchaf yr integreiddiad llai’r integryn amhendant ar lefel isaf yr integreiddiad.

$$\frac{2^{7}}{7}-\frac{8}{5}\times 2^{5}+\frac{16}{3}\times 2^{3}-\left(\frac{\left(-2\right)^{7}}{7}-\frac{8}{5}\left(-2\right)^{5}+\frac{16}{3}\left(-2\right)^{3}\right)$$

Symleiddio.

$$\frac{2048}{105}$$