Datrys ∫ (8/7-1/2)^2+(3/4-3/7)^2

$$\int ( \frac { 8 } { 7 } - \frac { 1 } { 2 } ) ^ { 2 } + ( \frac { 3 } { 4 } - \frac { 3 } { 7 } ) ^ { 2 }$$

Enrhifo

$$\frac{405x}{784}+С$$

Camau Ateb

Tynnu \frac{1}{2} o \frac{8}{7} i gael \frac{9}{14}.

$$\int \left(\frac{9}{14}\right)^{2}+\left(\frac{3}{4}-\frac{3}{7}\right)^{2}\mathrm{d}x$$

Cyfrifo \frac{9}{14} i bŵer 2 a chael \frac{81}{196}.

$$\int \frac{81}{196}+\left(\frac{3}{4}-\frac{3}{7}\right)^{2}\mathrm{d}x$$

Tynnu \frac{3}{7} o \frac{3}{4} i gael \frac{9}{28}.

$$\int \frac{81}{196}+\left(\frac{9}{28}\right)^{2}\mathrm{d}x$$

Cyfrifo \frac{9}{28} i bŵer 2 a chael \frac{81}{784}.

$$\int \frac{81}{196}+\frac{81}{784}\mathrm{d}x$$

Adio \frac{81}{196} a \frac{81}{784} i gael \frac{405}{784}.

$$\int \frac{405}{784}\mathrm{d}x$$

Canfod integryn \frac{405}{784} gan ddefnyddio'r rheol tabl o integrynnau cyffredin \int a\mathrm{d}x=ax.

$$\frac{405x}{784}$$

Os yw F\left(x\right) yn integryn amhendant o f\left(x\right), yna bydd F\left(x\right)+C yn rhoi’r set o holl integrynnau amhendant f\left(x\right). Felly, ychwanegwch gysonyn yr integryn C\in \mathrm{R} at y canlyniad.

$$\frac{405x}{784}+С$$

Gwahaniaethu w.r.t. x

$$\frac{405}{784} = 0.5165816326530612$$