Datrys x^2/x^2+6x+9-4/x^2-9=

$$\frac { x ^ { 2 } } { x ^ { 2 } + 6 x + 9 } - \frac { 4 } { x ^ { 2 } - 9 } =$$

Enrhifo

$$\frac{x^{3}-3x^{2}-4x-12}{\left(x-3\right)\left(x+3\right)^{2}}$$

Camau Ateb Byr

Ffactora x^{2}+6x+9. Ffactora x^{2}-9.

$$\frac{x^{2}}{\left(x+3\right)^{2}}-\frac{4}{\left(x-3\right)\left(x+3\right)}$$

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluosrif lleiaf cyffredin \left(x+3\right)^{2} a \left(x-3\right)\left(x+3\right) yw \left(x-3\right)\left(x+3\right)^{2}. Lluoswch \frac{x^{2}}{\left(x+3\right)^{2}} â \frac{x-3}{x-3}. Lluoswch \frac{4}{\left(x-3\right)\left(x+3\right)} â \frac{x+3}{x+3}.

$$\frac{x^{2}\left(x-3\right)}{\left(x-3\right)\left(x+3\right)^{2}}-\frac{4\left(x+3\right)}{\left(x-3\right)\left(x+3\right)^{2}}$$

Gan fod gan \frac{x^{2}\left(x-3\right)}{\left(x-3\right)\left(x+3\right)^{2}} a \frac{4\left(x+3\right)}{\left(x-3\right)\left(x+3\right)^{2}} yr un dynodydd, tynnwch nhw drwy dynnu eu rhifiaduron.

$$\frac{x^{2}\left(x-3\right)-4\left(x+3\right)}{\left(x-3\right)\left(x+3\right)^{2}}$$

Gwnewch y gwaith lluosi yn x^{2}\left(x-3\right)-4\left(x+3\right).

$$\frac{x^{3}-3x^{2}-4x-12}{\left(x-3\right)\left(x+3\right)^{2}}$$

Ehangu \left(x-3\right)\left(x+3\right)^{2}.

$$\frac{x^{3}-3x^{2}-4x-12}{x^{3}+3x^{2}-9x-27}$$

Gwahaniaethu w.r.t. x

$$\frac{2x\left(3x^{2}-14x+39\right)}{\left(x-3\right)^{2}\left(x+3\right)^{3}}$$