Datrys ar gyfer ξ
\xi =\left(1+2i\right)y+\left(-7+2i\right)
Datrys ar gyfer y
y=\left(\frac{1}{5}-\frac{2}{5}i\right)\xi +\left(\frac{3}{5}-\frac{16}{5}i\right)
Rhannu
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\frac{3}{1+2i}+\frac{\xi }{1+2i}=y+2i
Rhannu pob term 3+\xi â 1+2i i gael \frac{3}{1+2i}+\frac{\xi }{1+2i}.
\frac{3\left(1-2i\right)}{\left(1+2i\right)\left(1-2i\right)}+\frac{\xi }{1+2i}=y+2i
Lluoswch rifiadur ac enwadur \frac{3}{1+2i} gyda chyfiau cymhleth yr enwadur 1-2i.
\frac{3-6i}{5}+\frac{\xi }{1+2i}=y+2i
Gwnewch y gwaith lluosi yn \frac{3\left(1-2i\right)}{\left(1+2i\right)\left(1-2i\right)}.
\frac{3}{5}-\frac{6}{5}i+\frac{\xi }{1+2i}=y+2i
Rhannu 3-6i â 5 i gael \frac{3}{5}-\frac{6}{5}i.
\frac{\xi }{1+2i}=y+2i-\left(\frac{3}{5}-\frac{6}{5}i\right)
Tynnu \frac{3}{5}-\frac{6}{5}i o'r ddwy ochr.
\frac{\xi }{1+2i}=y+2i+\left(-\frac{3}{5}+\frac{6}{5}i\right)
Lluosi -1 a \frac{3}{5}-\frac{6}{5}i i gael -\frac{3}{5}+\frac{6}{5}i.
\frac{\xi }{1+2i}=y-\frac{3}{5}+\frac{16}{5}i
Gwnewch y gwaith adio yn 2i+\left(-\frac{3}{5}+\frac{6}{5}i\right).
\left(\frac{1}{5}-\frac{2}{5}i\right)\xi =y+\left(-\frac{3}{5}+\frac{16}{5}i\right)
Mae'r hafaliad yn y ffurf safonol.
\frac{\left(\frac{1}{5}-\frac{2}{5}i\right)\xi }{\frac{1}{5}-\frac{2}{5}i}=\frac{y+\left(-\frac{3}{5}+\frac{16}{5}i\right)}{\frac{1}{5}-\frac{2}{5}i}
Rhannu’r ddwy ochr â \frac{1}{5}-\frac{2}{5}i.
\xi =\frac{y+\left(-\frac{3}{5}+\frac{16}{5}i\right)}{\frac{1}{5}-\frac{2}{5}i}
Mae rhannu â \frac{1}{5}-\frac{2}{5}i yn dad-wneud lluosi â \frac{1}{5}-\frac{2}{5}i.
\xi =\left(1+2i\right)y+\left(-7+2i\right)
Rhannwch y+\left(-\frac{3}{5}+\frac{16}{5}i\right) â \frac{1}{5}-\frac{2}{5}i.
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