Datrys (2+1/x)^2/1+x-(1-1/x)^2*(x+1/x-2)-frac{2x+1}{x^2+x}

$$\frac { ( 2 + \frac { 1 } { x } ) ^ { 2 } } { 1 + x } - ( 1 - \frac { 1 } { x } ) ^ { 2 } \cdot ( x + \frac { 1 } { x } - 2 ) - \frac { 2 x + 1 } { x ^ { 2 } + x }$$

Enrhifo

$$-x+4-\frac{4}{x}+\frac{5}{x^{2}}-\frac{1}{x^{3}}$$

Camau Ateb Byr

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluoswch 2 â \frac{x}{x}.

$$\frac{\left(\frac{2x}{x}+\frac{1}{x}\right)^{2}}{1+x}-\left(1-\frac{1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

Gan fod gan \frac{2x}{x} a \frac{1}{x} yr un dynodydd, adiwch nhw drwy adio eu rhifiaduron.

$$\frac{\left(\frac{2x+1}{x}\right)^{2}}{1+x}-\left(1-\frac{1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

I godi \frac{2x+1}{x} i bŵer, codwch y rhifiadur a'r enwadur i bŵer ac yna rhannwch nhw.

$$\frac{\frac{\left(2x+1\right)^{2}}{x^{2}}}{1+x}-\left(1-\frac{1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

Mynegwch \frac{\frac{\left(2x+1\right)^{2}}{x^{2}}}{1+x} fel ffracsiwn unigol.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\left(1-\frac{1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluoswch 1 â \frac{x}{x}.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\left(\frac{x}{x}-\frac{1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

Gan fod gan \frac{x}{x} a \frac{1}{x} yr un dynodydd, tynnwch nhw drwy dynnu eu rhifiaduron.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\left(\frac{x-1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

I godi \frac{x-1}{x} i bŵer, codwch y rhifiadur a'r enwadur i bŵer ac yna rhannwch nhw.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}}{x^{2}}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluoswch x-2 â \frac{x}{x}.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}}{x^{2}}\left(\frac{\left(x-2\right)x}{x}+\frac{1}{x}\right)-\frac{2x+1}{x^{2}+x}$$

Gan fod gan \frac{\left(x-2\right)x}{x} a \frac{1}{x} yr un dynodydd, adiwch nhw drwy adio eu rhifiaduron.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}}{x^{2}}\times \frac{\left(x-2\right)x+1}{x}-\frac{2x+1}{x^{2}+x}$$

Gwnewch y gwaith lluosi yn \left(x-2\right)x+1.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}}{x^{2}}\times \frac{x^{2}-2x+1}{x}-\frac{2x+1}{x^{2}+x}$$

Lluoswch \frac{\left(x-1\right)^{2}}{x^{2}} â \frac{x^{2}-2x+1}{x} drwy luosi'r rhifiadur â’r rhifiadur a'r enwadur â’r enwadur.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}\left(x^{2}-2x+1\right)}{x^{2}x}-\frac{2x+1}{x^{2}+x}$$

Er mwyn lluosi pwerau sy’n rhannu’r un sail, adiwch eu esbonyddion. Adiwch 2 a 1 i gael 3.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}\left(x^{2}-2x+1\right)}{x^{3}}-\frac{2x+1}{x^{2}+x}$$

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluosrif lleiaf cyffredin x^{2}\left(1+x\right) a x^{3} yw \left(x+1\right)x^{3}. Lluoswch \frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)} â \frac{x}{x}. Lluoswch \frac{\left(x-1\right)^{2}\left(x^{2}-2x+1\right)}{x^{3}} â \frac{x+1}{x+1}.

$$\frac{\left(2x+1\right)^{2}x}{\left(x+1\right)x^{3}}-\frac{\left(x-1\right)^{2}\left(x^{2}-2x+1\right)\left(x+1\right)}{\left(x+1\right)x^{3}}-\frac{2x+1}{x^{2}+x}$$

Gan fod gan \frac{\left(2x+1\right)^{2}x}{\left(x+1\right)x^{3}} a \frac{\left(x-1\right)^{2}\left(x^{2}-2x+1\right)\left(x+1\right)}{\left(x+1\right)x^{3}} yr un dynodydd, tynnwch nhw drwy dynnu eu rhifiaduron.

$$\frac{\left(2x+1\right)^{2}x-\left(x-1\right)^{2}\left(x^{2}-2x+1\right)\left(x+1\right)}{\left(x+1\right)x^{3}}-\frac{2x+1}{x^{2}+x}$$

Gwnewch y gwaith lluosi yn \left(2x+1\right)^{2}x-\left(x-1\right)^{2}\left(x^{2}-2x+1\right)\left(x+1\right).

$$\frac{4x^{3}+4x^{2}+x-x^{5}+x^{4}+x^{3}-x^{2}+2x^{4}-2x^{3}-2x^{2}+2x-x^{3}+x^{2}+x-1}{\left(x+1\right)x^{3}}-\frac{2x+1}{x^{2}+x}$$

Cyfuno termau tebyg yn 4x^{3}+4x^{2}+x-x^{5}+x^{4}+x^{3}-x^{2}+2x^{4}-2x^{3}-2x^{2}+2x-x^{3}+x^{2}+x-1.

$$\frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}}-\frac{2x+1}{x^{2}+x}$$

Ffactora x^{2}+x.

$$\frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}}-\frac{2x+1}{x\left(x+1\right)}$$

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluosrif lleiaf cyffredin \left(x+1\right)x^{3} a x\left(x+1\right) yw \left(x+1\right)x^{3}. Lluoswch \frac{2x+1}{x\left(x+1\right)} â \frac{x^{2}}{x^{2}}.

$$\frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}}-\frac{\left(2x+1\right)x^{2}}{\left(x+1\right)x^{3}}$$

Gan fod gan \frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}} a \frac{\left(2x+1\right)x^{2}}{\left(x+1\right)x^{3}} yr un dynodydd, tynnwch nhw drwy dynnu eu rhifiaduron.

$$\frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1-\left(2x+1\right)x^{2}}{\left(x+1\right)x^{3}}$$

Gwnewch y gwaith lluosi yn 2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1-\left(2x+1\right)x^{2}.

$$\frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1-2x^{3}-x^{2}}{\left(x+1\right)x^{3}}$$

Cyfuno termau tebyg yn 2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1-2x^{3}-x^{2}.

$$\frac{x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}}$$

Dylech ffactoreiddio'r mynegiadau sydd heb eu ffactoreiddio eisoes yn \frac{x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}}.

$$\frac{\left(x+1\right)\left(-x^{4}+4x^{3}-4x^{2}+5x-1\right)}{\left(x+1\right)x^{3}}$$

Canslo x+1 yn y rhifiadur a'r enwadur.

$$\frac{-x^{4}+4x^{3}-4x^{2}+5x-1}{x^{3}}$$

Ehangu

$$-x+4-\frac{4}{x}+\frac{5}{x^{2}}-\frac{1}{x^{3}}$$

Camau Ateb Byr

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluoswch 2 â \frac{x}{x}.

$$\frac{\left(\frac{2x}{x}+\frac{1}{x}\right)^{2}}{1+x}-\left(1-\frac{1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

Gan fod gan \frac{2x}{x} a \frac{1}{x} yr un dynodydd, adiwch nhw drwy adio eu rhifiaduron.

$$\frac{\left(\frac{2x+1}{x}\right)^{2}}{1+x}-\left(1-\frac{1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

I godi \frac{2x+1}{x} i bŵer, codwch y rhifiadur a'r enwadur i bŵer ac yna rhannwch nhw.

$$\frac{\frac{\left(2x+1\right)^{2}}{x^{2}}}{1+x}-\left(1-\frac{1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

Mynegwch \frac{\frac{\left(2x+1\right)^{2}}{x^{2}}}{1+x} fel ffracsiwn unigol.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\left(1-\frac{1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluoswch 1 â \frac{x}{x}.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\left(\frac{x}{x}-\frac{1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

Gan fod gan \frac{x}{x} a \frac{1}{x} yr un dynodydd, tynnwch nhw drwy dynnu eu rhifiaduron.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\left(\frac{x-1}{x}\right)^{2}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

I godi \frac{x-1}{x} i bŵer, codwch y rhifiadur a'r enwadur i bŵer ac yna rhannwch nhw.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}}{x^{2}}\left(x+\frac{1}{x}-2\right)-\frac{2x+1}{x^{2}+x}$$

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluoswch x-2 â \frac{x}{x}.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}}{x^{2}}\left(\frac{\left(x-2\right)x}{x}+\frac{1}{x}\right)-\frac{2x+1}{x^{2}+x}$$

Gan fod gan \frac{\left(x-2\right)x}{x} a \frac{1}{x} yr un dynodydd, adiwch nhw drwy adio eu rhifiaduron.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}}{x^{2}}\times \frac{\left(x-2\right)x+1}{x}-\frac{2x+1}{x^{2}+x}$$

Gwnewch y gwaith lluosi yn \left(x-2\right)x+1.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}}{x^{2}}\times \frac{x^{2}-2x+1}{x}-\frac{2x+1}{x^{2}+x}$$

Lluoswch \frac{\left(x-1\right)^{2}}{x^{2}} â \frac{x^{2}-2x+1}{x} drwy luosi'r rhifiadur â’r rhifiadur a'r enwadur â’r enwadur.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}\left(x^{2}-2x+1\right)}{x^{2}x}-\frac{2x+1}{x^{2}+x}$$

Er mwyn lluosi pwerau sy’n rhannu’r un sail, adiwch eu esbonyddion. Adiwch 2 a 1 i gael 3.

$$\frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)}-\frac{\left(x-1\right)^{2}\left(x^{2}-2x+1\right)}{x^{3}}-\frac{2x+1}{x^{2}+x}$$

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluosrif lleiaf cyffredin x^{2}\left(1+x\right) a x^{3} yw \left(x+1\right)x^{3}. Lluoswch \frac{\left(2x+1\right)^{2}}{x^{2}\left(1+x\right)} â \frac{x}{x}. Lluoswch \frac{\left(x-1\right)^{2}\left(x^{2}-2x+1\right)}{x^{3}} â \frac{x+1}{x+1}.

$$\frac{\left(2x+1\right)^{2}x}{\left(x+1\right)x^{3}}-\frac{\left(x-1\right)^{2}\left(x^{2}-2x+1\right)\left(x+1\right)}{\left(x+1\right)x^{3}}-\frac{2x+1}{x^{2}+x}$$

Gan fod gan \frac{\left(2x+1\right)^{2}x}{\left(x+1\right)x^{3}} a \frac{\left(x-1\right)^{2}\left(x^{2}-2x+1\right)\left(x+1\right)}{\left(x+1\right)x^{3}} yr un dynodydd, tynnwch nhw drwy dynnu eu rhifiaduron.

$$\frac{\left(2x+1\right)^{2}x-\left(x-1\right)^{2}\left(x^{2}-2x+1\right)\left(x+1\right)}{\left(x+1\right)x^{3}}-\frac{2x+1}{x^{2}+x}$$

Gwnewch y gwaith lluosi yn \left(2x+1\right)^{2}x-\left(x-1\right)^{2}\left(x^{2}-2x+1\right)\left(x+1\right).

$$\frac{4x^{3}+4x^{2}+x-x^{5}+x^{4}+x^{3}-x^{2}+2x^{4}-2x^{3}-2x^{2}+2x-x^{3}+x^{2}+x-1}{\left(x+1\right)x^{3}}-\frac{2x+1}{x^{2}+x}$$

Cyfuno termau tebyg yn 4x^{3}+4x^{2}+x-x^{5}+x^{4}+x^{3}-x^{2}+2x^{4}-2x^{3}-2x^{2}+2x-x^{3}+x^{2}+x-1.

$$\frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}}-\frac{2x+1}{x^{2}+x}$$

Ffactora x^{2}+x.

$$\frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}}-\frac{2x+1}{x\left(x+1\right)}$$

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluosrif lleiaf cyffredin \left(x+1\right)x^{3} a x\left(x+1\right) yw \left(x+1\right)x^{3}. Lluoswch \frac{2x+1}{x\left(x+1\right)} â \frac{x^{2}}{x^{2}}.

$$\frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}}-\frac{\left(2x+1\right)x^{2}}{\left(x+1\right)x^{3}}$$

Gan fod gan \frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}} a \frac{\left(2x+1\right)x^{2}}{\left(x+1\right)x^{3}} yr un dynodydd, tynnwch nhw drwy dynnu eu rhifiaduron.

$$\frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1-\left(2x+1\right)x^{2}}{\left(x+1\right)x^{3}}$$

Gwnewch y gwaith lluosi yn 2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1-\left(2x+1\right)x^{2}.

$$\frac{2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1-2x^{3}-x^{2}}{\left(x+1\right)x^{3}}$$

Cyfuno termau tebyg yn 2x^{3}+2x^{2}+4x-x^{5}+3x^{4}-1-2x^{3}-x^{2}.

$$\frac{x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}}$$

Dylech ffactoreiddio'r mynegiadau sydd heb eu ffactoreiddio eisoes yn \frac{x^{2}+4x-x^{5}+3x^{4}-1}{\left(x+1\right)x^{3}}.

$$\frac{\left(x+1\right)\left(-x^{4}+4x^{3}-4x^{2}+5x-1\right)}{\left(x+1\right)x^{3}}$$

Canslo x+1 yn y rhifiadur a'r enwadur.

$$\frac{-x^{4}+4x^{3}-4x^{2}+5x-1}{x^{3}}$$