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Problemau tebyg o chwiliad gwe

Rhannu

\left(\frac{\sqrt{6}-\sqrt{2}}{4}\right)^{2}
Lluosi \frac{\sqrt{6}-\sqrt{2}}{4} a \frac{\sqrt{6}-\sqrt{2}}{4} i gael \left(\frac{\sqrt{6}-\sqrt{2}}{4}\right)^{2}.
\frac{\left(\sqrt{6}-\sqrt{2}\right)^{2}}{4^{2}}
I godi \frac{\sqrt{6}-\sqrt{2}}{4} i bŵer, codwch y rhifiadur a'r enwadur i bŵer ac yna rhannwch nhw.
\frac{\left(\sqrt{6}\right)^{2}-2\sqrt{6}\sqrt{2}+\left(\sqrt{2}\right)^{2}}{4^{2}}
Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(\sqrt{6}-\sqrt{2}\right)^{2}.
\frac{6-2\sqrt{6}\sqrt{2}+\left(\sqrt{2}\right)^{2}}{4^{2}}
Sgwâr \sqrt{6} yw 6.
\frac{6-2\sqrt{2}\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}}{4^{2}}
Ffactora 6=2\times 3. Ailysgrifennu ail isradd y lluoswm \sqrt{2\times 3} fel lluoswm ail israddau \sqrt{2}\sqrt{3}.
\frac{6-2\times 2\sqrt{3}+\left(\sqrt{2}\right)^{2}}{4^{2}}
Lluosi \sqrt{2} a \sqrt{2} i gael 2.
\frac{6-4\sqrt{3}+\left(\sqrt{2}\right)^{2}}{4^{2}}
Lluosi -2 a 2 i gael -4.
\frac{6-4\sqrt{3}+2}{4^{2}}
Sgwâr \sqrt{2} yw 2.
\frac{8-4\sqrt{3}}{4^{2}}
Adio 6 a 2 i gael 8.
\frac{8-4\sqrt{3}}{16}
Cyfrifo 4 i bŵer 2 a chael 16.