Datrys 1/1+t+1/1-t-2/3t^2=

$$\frac { \frac { 1 } { 1 + t } + \frac { 1 } { 1 - t } - 2 } { 3 t ^ { 2 } } =$$

Enrhifo

$$\frac{2}{3\left(1-t^{2}\right)}$$

Camau Ateb Byr

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluosrif lleiaf cyffredin 1+t a 1-t yw \left(t+1\right)\left(-t+1\right). Lluoswch \frac{1}{1+t} â \frac{-t+1}{-t+1}. Lluoswch \frac{1}{1-t} â \frac{t+1}{t+1}.

$$\frac{\frac{-t+1}{\left(t+1\right)\left(-t+1\right)}+\frac{t+1}{\left(t+1\right)\left(-t+1\right)}-2}{3t^{2}}$$

Gan fod gan \frac{-t+1}{\left(t+1\right)\left(-t+1\right)} a \frac{t+1}{\left(t+1\right)\left(-t+1\right)} yr un dynodydd, adiwch nhw drwy adio eu rhifiaduron.

$$\frac{\frac{-t+1+t+1}{\left(t+1\right)\left(-t+1\right)}-2}{3t^{2}}$$

Cyfuno termau tebyg yn -t+1+t+1.

$$\frac{\frac{2}{\left(t+1\right)\left(-t+1\right)}-2}{3t^{2}}$$

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluoswch 2 â \frac{\left(t+1\right)\left(-t+1\right)}{\left(t+1\right)\left(-t+1\right)}.

$$\frac{\frac{2}{\left(t+1\right)\left(-t+1\right)}-\frac{2\left(t+1\right)\left(-t+1\right)}{\left(t+1\right)\left(-t+1\right)}}{3t^{2}}$$

Gan fod gan \frac{2}{\left(t+1\right)\left(-t+1\right)} a \frac{2\left(t+1\right)\left(-t+1\right)}{\left(t+1\right)\left(-t+1\right)} yr un dynodydd, tynnwch nhw drwy dynnu eu rhifiaduron.

$$\frac{\frac{2-2\left(t+1\right)\left(-t+1\right)}{\left(t+1\right)\left(-t+1\right)}}{3t^{2}}$$

Gwnewch y gwaith lluosi yn 2-2\left(t+1\right)\left(-t+1\right).

$$\frac{\frac{2+2t^{2}-2t+2t-2}{\left(t+1\right)\left(-t+1\right)}}{3t^{2}}$$

Cyfuno termau tebyg yn 2+2t^{2}-2t+2t-2.

$$\frac{\frac{2t^{2}}{\left(t+1\right)\left(-t+1\right)}}{3t^{2}}$$

Mynegwch \frac{\frac{2t^{2}}{\left(t+1\right)\left(-t+1\right)}}{3t^{2}} fel ffracsiwn unigol.

$$\frac{2t^{2}}{\left(t+1\right)\left(-t+1\right)\times 3t^{2}}$$

Canslo t^{2} yn y rhifiadur a'r enwadur.

$$\frac{2}{3\left(t+1\right)\left(-t+1\right)}$$

Defnyddio’r briodwedd ddosbarthu i luosi 3 â t+1.

$$\frac{2}{\left(3t+3\right)\left(-t+1\right)}$$

Defnyddio’r briodwedd ddosbarthu i luosi 3t+3 â -t+1 a chyfuno termau tebyg.

$$\frac{2}{-3t^{2}+3}$$

Ehangu

$$\frac{2}{3\left(1-t^{2}\right)}$$

Camau Ateb Byr

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluosrif lleiaf cyffredin 1+t a 1-t yw \left(t+1\right)\left(-t+1\right). Lluoswch \frac{1}{1+t} â \frac{-t+1}{-t+1}. Lluoswch \frac{1}{1-t} â \frac{t+1}{t+1}.

$$\frac{\frac{-t+1}{\left(t+1\right)\left(-t+1\right)}+\frac{t+1}{\left(t+1\right)\left(-t+1\right)}-2}{3t^{2}}$$

Gan fod gan \frac{-t+1}{\left(t+1\right)\left(-t+1\right)} a \frac{t+1}{\left(t+1\right)\left(-t+1\right)} yr un dynodydd, adiwch nhw drwy adio eu rhifiaduron.

$$\frac{\frac{-t+1+t+1}{\left(t+1\right)\left(-t+1\right)}-2}{3t^{2}}$$

Cyfuno termau tebyg yn -t+1+t+1.

$$\frac{\frac{2}{\left(t+1\right)\left(-t+1\right)}-2}{3t^{2}}$$

I ychwanegu neu dynnu mynegiannau, rhaid i chi eu ehangu i wneud eu enwaduron yr un fath. Lluoswch 2 â \frac{\left(t+1\right)\left(-t+1\right)}{\left(t+1\right)\left(-t+1\right)}.

$$\frac{\frac{2}{\left(t+1\right)\left(-t+1\right)}-\frac{2\left(t+1\right)\left(-t+1\right)}{\left(t+1\right)\left(-t+1\right)}}{3t^{2}}$$

Gan fod gan \frac{2}{\left(t+1\right)\left(-t+1\right)} a \frac{2\left(t+1\right)\left(-t+1\right)}{\left(t+1\right)\left(-t+1\right)} yr un dynodydd, tynnwch nhw drwy dynnu eu rhifiaduron.

$$\frac{\frac{2-2\left(t+1\right)\left(-t+1\right)}{\left(t+1\right)\left(-t+1\right)}}{3t^{2}}$$

Gwnewch y gwaith lluosi yn 2-2\left(t+1\right)\left(-t+1\right).

$$\frac{\frac{2+2t^{2}-2t+2t-2}{\left(t+1\right)\left(-t+1\right)}}{3t^{2}}$$

Cyfuno termau tebyg yn 2+2t^{2}-2t+2t-2.

$$\frac{\frac{2t^{2}}{\left(t+1\right)\left(-t+1\right)}}{3t^{2}}$$

Mynegwch \frac{\frac{2t^{2}}{\left(t+1\right)\left(-t+1\right)}}{3t^{2}} fel ffracsiwn unigol.

$$\frac{2t^{2}}{\left(t+1\right)\left(-t+1\right)\times 3t^{2}}$$

Canslo t^{2} yn y rhifiadur a'r enwadur.

$$\frac{2}{3\left(t+1\right)\left(-t+1\right)}$$

Defnyddio’r briodwedd ddosbarthu i luosi 3 â t+1.

$$\frac{2}{\left(3t+3\right)\left(-t+1\right)}$$

Defnyddio’r briodwedd ddosbarthu i luosi 3t+3 â -t+1 a chyfuno termau tebyg.

$$\frac{2}{-3t^{2}+3}$$