Datrys alphabeta^2+alpha^2beta=alphabeta(alpha+beta)=

$$\alpha \beta ^ { 2 } + \alpha ^ { 2 } \beta = \alpha \beta ( \alpha + \beta ) =$$

Datrys ar gyfer α

$$\alpha \in \mathrm{R}$$

Camau Ateb

Defnyddio’r briodwedd ddosbarthu i luosi \alpha \beta â \alpha +\beta .

$$\alpha \beta ^{2}+\alpha ^{2}\beta =\beta \alpha ^{2}+\alpha \beta ^{2}$$

Tynnu \beta \alpha ^{2} o'r ddwy ochr.

$$\alpha \beta ^{2}+\alpha ^{2}\beta -\beta \alpha ^{2}=\alpha \beta ^{2}$$

Cyfuno \alpha ^{2}\beta a -\beta \alpha ^{2} i gael 0.

$$\alpha \beta ^{2}=\alpha \beta ^{2}$$

Tynnu \alpha \beta ^{2} o'r ddwy ochr.

$$\alpha \beta ^{2}-\alpha \beta ^{2}=0$$

Cyfuno \alpha \beta ^{2} a -\alpha \beta ^{2} i gael 0.

$$0=0$$

Cymharu 0 gyda 0.

$$\text{true}$$

Mae hyn yn wir ar gyfer unrhyw \alpha .

$$\alpha \in \mathrm{R}$$

Datrys ar gyfer β

$$\beta \in \mathrm{R}$$

Camau Ateb

Defnyddio’r briodwedd ddosbarthu i luosi \alpha \beta â \alpha +\beta .

$$\alpha \beta ^{2}+\alpha ^{2}\beta =\beta \alpha ^{2}+\alpha \beta ^{2}$$

Tynnu \beta \alpha ^{2} o'r ddwy ochr.

$$\alpha \beta ^{2}+\alpha ^{2}\beta -\beta \alpha ^{2}=\alpha \beta ^{2}$$

Cyfuno \alpha ^{2}\beta a -\beta \alpha ^{2} i gael 0.

$$\alpha \beta ^{2}=\alpha \beta ^{2}$$

Tynnu \alpha \beta ^{2} o'r ddwy ochr.

$$\alpha \beta ^{2}-\alpha \beta ^{2}=0$$

Cyfuno \alpha \beta ^{2} a -\alpha \beta ^{2} i gael 0.

$$0=0$$

Cymharu 0 gyda 0.

$$\text{true}$$

Mae hyn yn wir ar gyfer unrhyw \beta .

$$\beta \in \mathrm{R}$$