Microsoft Math Solver
求解
练习
下载
Solve
Practice
主题
算术
平均值
模式
最大公因数
最小公倍数
操作顺序
分数
带分数
素因数分解
指数
激进分子
代数
合并喜欢的条款
变量求解
因子
展开
评估分数
线性方程组
二次方程
不等式
方程组
矩阵
三角学
简化
评价
图表
解方程
微积分
衍生物
积分
限制
几何计算器
三角函数计算器
微积分计算器
矩阵计算器
下载
主题
算术
平均值
模式
最大公因数
最小公倍数
操作顺序
分数
带分数
素因数分解
指数
激进分子
代数
合并喜欢的条款
变量求解
因子
展开
评估分数
线性方程组
二次方程
不等式
方程组
矩阵
三角学
简化
评价
图表
解方程
微积分
衍生物
积分
限制
几何计算器
三角函数计算器
微积分计算器
矩阵计算器
求解
代数
三角学
统计
微积分
矩阵
变数
列表
mode(2,4,5,3,2,4,5,6,4,3,2)
求值
2,4
测验
5 道与此类似的题目:
mode(2,4,5,3,2,4,5,6,4,3,2)
来自 Web 搜索的类似问题
mn+1 \equiv 0 \pmod{24} then : m+n \equiv 0 \pmod{24} using group theory
https://math.stackexchange.com/questions/2350421/mn1-equiv-0-pmod24-then-mn-equiv-0-pmod24-using-group-theory
You're trying to prove that if mn \equiv -1 \pmod{24} then m \equiv -n \pmod{24}. Let k = -n. Then you're trying to show that if -mk \equiv -1 \pmod{24} then m \equiv k \pmod{24}. Of ...
Can we ever have \Gamma \models \perp
https://math.stackexchange.com/questions/2639449/can-we-ever-have-gamma-models-perp
That's exactly right: "\Gamma\models\perp" is equivalent to "\Gamma has no model" (or "\Gamma is unsatisfiable").
Is this proof about Mersenne numbers acceptable?
https://math.stackexchange.com/questions/86429/is-this-proof-about-mersenne-numbers-acceptable
There is nothing incorrect, but there are a few things that could be changed. We only need p>2. From 2^p \equiv 2 \pmod {p} one should conclude M_p=2^p -1\equiv 1 \pmod{p} immediately, without ...
Solving system of linear congruence equations
https://math.stackexchange.com/questions/473711/solving-system-of-linear-congruence-equations
The way you express your congruences is rather unconventional. Given that 23d\equiv1\pmod{40}, 73d\equiv1\pmod{102}, and that 40=2^3\times5 and 102=2\times3\times17, it follows that 23d\equiv1\pmod5, ...
How to prove an element of a given structure is not definable?
https://math.stackexchange.com/questions/927915/how-to-prove-an-element-of-a-given-structure-is-not-definable
HINT: If x is a definable element in a structure \mathcal M, then any automorphism of \cal M must satisfy f(x)=x. To show that 2 is not definable, find an automorphism of \cal A such that ...
The deduction theorem according to AIMA
https://math.stackexchange.com/questions/13251/the-deduction-theorem-according-to-aima
In order for \alpha\Rightarrow\beta to be valid, it must hold in all models; for \alpha\Rightarrow\beta to not be valid, there must be a model where it is false. If there is a model where it is ...
更多结果
共享
复制
已复制到剪贴板
类似问题
mode(1,2,3,2,1,2,3)
mode(1,2,3)
mode(20,34,32,35,45,32,45,32,32)
mode(2,4,5,3,2,4,5,6,4,3,2)
mode(10,11,10,12)
mode(1,1,2,2,3,3)
回到顶部
