解決y=tan(2x-pi) |Microsoft數學求解器

$$y= \tan ( 2x- \pi )$$

解 y (復數求解)

$$y=-\tan(-2x)$$

$$\nexists n_{1}\in \mathrm{Z}\text{ : }x=\frac{\pi n_{1}}{2}+\frac{\pi }{4}$$

解 x

$$x=\pi n_{4}+\pi +\frac{1}{2}arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})\text{, }n_{4}\in \mathrm{Z}\text{, }\exists n_{43}\in \mathrm{Z}\text{ : }\left(n_{4}>-\frac{1}{4}+\left(-\frac{1}{2}\right)\pi ^{-1}arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})+\frac{1}{2}n_{43}\text{ and }n_{4}<\frac{1}{4}+\left(-\frac{1}{2}\right)\pi ^{-1}arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})+\frac{1}{2}n_{43}\right)$$

$$x=\frac{1}{2}\pi +\frac{1}{2}arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})+\pi n_{23}\text{, }n_{23}\in \mathrm{Z}\text{, }\exists n_{43}\in \mathrm{Z}\text{ : }\left(n_{43}<\pi ^{-1}arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})-\frac{1}{2}+2n_{23}\text{ and }n_{43}>\pi ^{-1}arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})-\frac{3}{2}+2n_{23}\right)$$

解 y

$$y=\tan(2x)$$

$$\nexists n_{1}\in \mathrm{Z}\text{ : }x=\frac{\pi n_{1}}{2}+\frac{\pi }{4}$$