解決t_{2}=frac{ln(frac{x_{m}}{x_{0}}-1)+(.31)}{r_{0}} |Microsoft數學求解器

$$t _ { 2 } = \frac { \ln ( \frac { x _ { m } } { x _ { 0 } } - 1 ) + ( .31 ) } { r _ { 0 } }$$

解 r_0 (復數求解)

$$\left\{\begin{matrix}\\r_{0}\neq 0\text{, }&\text{unconditionally}\\r_{0}=\frac{\ln(\frac{x_{m}}{x_{0}}-1)}{t_{2}}+\frac{31}{100t_{2}}\text{, }&x_{m}\neq \frac{x_{0}}{e^{\frac{31}{100}}}+x_{0}\text{ and }t_{2}\neq 0\text{ and }x_{m}\neq x_{0}\text{ and }x_{0}\neq 0\end{matrix}\right.$$

解 t_2 (復數求解)

$$t_{2}=\frac{\ln(\frac{x_{m}}{x_{0}}-1)}{r_{0}}+\frac{31}{100r_{0}}$$

$$r_{0}\neq 0\text{ and }x_{m}\neq x_{0}\text{ and }x_{0}\neq 0$$

解 r_0

$$\left\{\begin{matrix}\\r_{0}\neq 0\text{, }&\text{unconditionally}\\r_{0}=\frac{\ln(\frac{x_{m}}{x_{0}}-1)}{t_{2}}+\frac{31}{100t_{2}}\text{, }&x_{m}\neq \frac{x_{0}}{e^{\frac{31}{100}}}+x_{0}\text{ and }t_{2}\neq 0\text{ and }x_{m}\neq x_{0}\text{ and }\left(x_{m}<x_{0}\text{ or }x_{0}>0\right)\text{ and }\left(x_{0}<0\text{ or }x_{m}>x_{0}\right)\text{ and }x_{0}\neq 0\end{matrix}\right.$$

解 t_2

$$t_{2}=\frac{\ln(\frac{x_{m}}{x_{0}}-1)}{r_{0}}+\frac{31}{100r_{0}}$$

$$\left(r_{0}\neq 0\text{ and }x_{m}<x_{0}\text{ and }x_{0}<0\right)\text{ or }\left(r_{0}\neq 0\text{ and }x_{m}>x_{0}\text{ and }x_{0}>0\right)$$