解決h(u)=(3u^2+5)^3(3u-1)^2 |Microsoft數學求解器

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\left(27\left(u^{2}\right)^{3}+135\left(u^{2}\right)^{2}+225u^{2}+125\right)\left(3u-1\right)^{2}

使用二項式定理 \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} 展開 \left(3u^{2}+5\right)^{3}。

\left(27u^{6}+135\left(u^{2}\right)^{2}+225u^{2}+125\right)\left(3u-1\right)^{2}

計算某數乘冪之乘冪的方法: 將指數相乘。2 乘 3 得到 6。

\left(27u^{6}+135u^{4}+225u^{2}+125\right)\left(3u-1\right)^{2}

計算某數乘冪之乘冪的方法: 將指數相乘。2 乘 2 得到 4。

\left(27u^{6}+135u^{4}+225u^{2}+125\right)\left(9u^{2}-6u+1\right)

使用二項式定理 \left(a-b\right)^{2}=a^{2}-2ab+b^{2} 展開 \left(3u-1\right)^{2}。

243u^{8}-162u^{7}+1242u^{6}-810u^{5}+2160u^{4}-1350u^{3}+1350u^{2}-750u+125

計算 27u^{6}+135u^{4}+225u^{2}+125 乘上 9u^{2}-6u+1 時使用乘法分配律並合併同類項。