解決operatorname{sg}_{5}25-log_{5}(x+100)=-1 |Microsoft數學求解器

$$\operatorname { sg } _ { 5 } 25 - \log _ { 5 } ( x + 100 ) = - 1$$

解 g_5 (復數求解)

$$\left\{\begin{matrix}g_{5}=-\frac{-\log_{5}\left(x+100\right)+1}{25s}\text{, }&s\neq 0\text{ and }x\neq -100\\g_{5}\in \mathrm{C}\text{, }&s=0\text{ and }x=-95\end{matrix}\right.$$

解 s (復數求解)

$$\left\{\begin{matrix}s=-\frac{-\log_{5}\left(x+100\right)+1}{25g_{5}}\text{, }&g_{5}\neq 0\text{ and }x\neq -100\\s\in \mathrm{C}\text{, }&g_{5}=0\text{ and }x=-95\end{matrix}\right.$$

解 g_5

$$\left\{\begin{matrix}g_{5}=-\frac{-\log_{5}\left(x+100\right)+1}{25s}\text{, }&s\neq 0\text{ and }x>-100\\g_{5}\in \mathrm{R}\text{, }&s=0\text{ and }x=-95\end{matrix}\right.$$

解 s

$$\left\{\begin{matrix}s=-\frac{-\log_{5}\left(x+100\right)+1}{25g_{5}}\text{, }&g_{5}\neq 0\text{ and }x>-100\\s\in \mathrm{R}\text{, }&g_{5}=0\text{ and }x=-95\end{matrix}\right.$$