解決{l}{x^2=42}{y=x+pi}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b} |Microsoft數學求解器

$$\left. \begin{array} { l } { x ^ {2} = 42 }\\ { y = x + \pi }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

解 x、y、z、a、b、c

$$x=-\sqrt{42}\approx -6.480740698\text{, }y=\pi -\sqrt{42}\approx -3.339148045\text{, }z=\pi -\sqrt{42}\approx -3.339148045\text{, }a=\pi -\sqrt{42}\approx -3.339148045\text{, }b=\pi -\sqrt{42}\approx -3.339148045\text{, }c=\pi -\sqrt{42}\approx -3.339148045$$

$$x=\sqrt{42}\approx 6.480740698\text{, }y=\pi +\sqrt{42}\approx 9.622333352\text{, }z=\pi +\sqrt{42}\approx 9.622333352\text{, }a=\pi +\sqrt{42}\approx 9.622333352\text{, }b=\pi +\sqrt{42}\approx 9.622333352\text{, }c=\pi +\sqrt{42}\approx 9.622333352$$