解決(x+2)^2/25+(y-3)^2/9=1 |Microsoft數學求解器

解 x (復數求解)

x=-\frac{5i\sqrt{y}\sqrt{y-6}}{3}-2

x=\frac{5i\sqrt{y}\sqrt{y-6}}{3}-2

解 y (復數求解)

y=-\frac{3i\sqrt{x-3}\sqrt{x+7}}{5}+3

y=\frac{3i\sqrt{x-3}\sqrt{x+7}}{5}+3

解 x

x=\frac{-5\sqrt{y\left(6-y\right)}-6}{3}

x=\frac{5\sqrt{y\left(6-y\right)}-6}{3}\text{, }y\geq 0\text{ and }y\leq 6

解 y

y=\frac{3\left(-\sqrt{\left(3-x\right)\left(x+7\right)}+5\right)}{5}

y=\frac{3\left(\sqrt{\left(3-x\right)\left(x+7\right)}+5\right)}{5}\text{, }x\geq -7\text{ and }x\leq 3

圖表

測驗

Algebra

5類似於:

\frac { ( x + 2 ) ^ { 2 } } { 25 } + \frac { ( y - 3 ) ^ { 2 } } { 9 } = 1

來自 Web 搜索的類似問題

How do I graph the equation \displaystyle\frac{{\left({x}+{2}\right)}^{{2}}}{{9}}+\frac{{\left({y}-{3}\right)}^{{2}}}{{25}}={1} on an Nspire?

https://socratic.org/questions/how-do-i-graph-the-equation-x-2-2-9-y-3-2-25-1-on-an-nspire

MrsRudolph221 Apr 7, 2015 \displaystyle\frac{{{\left({x}+{2}\right)}^{{2}}}}{{9}}+\frac{{{\left({y}−{3}\right)}^{{2}}}}{{25}}={1} is an equation for an ellipse, which can easily be ...

How do you add or subtract \displaystyle\frac{{{4}{x}{y}}}{{{x}^{{2}}-{y}^{{2}}}}+\frac{{{x}-{y}}}{{{x}+{y}}} ?

https://socratic.org/questions/how-do-you-add-or-subtract-4xy-x-2-y-2-x-y-x-y

See a solution process below: Explanation: To add or subtract fractions they must be over a common denominator. \displaystyle{x}^{{2}}-{y}^{{2}}={\left({x}+{y}\right)}{\left({x}-{y}\right)} ...

How do you find all the critical points to graph \displaystyle\frac{{\left({x}-{2}\right)}^{{2}}}{{36}}+\frac{{\left({y}-{1}\right)}^{{2}}}{{36}}={1} including vertices, foci and asymptotes?

https://socratic.org/questions/how-do-you-find-all-the-critical-points-to-graph-x-2-2-36-y-1-2-36-1-including-v

Douglas K. Jan 2, 2017 There are no vertices, foci or asymptotes; it is a circle with its center at \displaystyle{\left({2},{1}\right)} and a radius of 6: \displaystyle{\left({x}-{2}\right)}+{\left({y}-{1}\right)}={6}^{{2}}

How do you find the vertices and foci of \displaystyle{\frac{{{\left({x}+{2}\right)}^{{{2}}}}}{{{16}}}}-{\frac{{{\left({y}-{2}\right)}^{{{2}}}}}{{{9}}}}={1} ?

https://socratic.org/questions/how-do-you-find-the-vertices-and-foci-of-frac-x-2-2-16-frac-y-2-2-9-1

Vertices are at \displaystyle{\left(-{6},{2}\right)}{\quad\text{and}\quad}{\left({2},{2}\right)} Focii are at \displaystyle{\left(-{7},{2}\right)}{\quad\text{and}\quad}{\left({3},{2}\right)} ...

How do you graph the ellipse \displaystyle\frac{{\left({x}-{2}\right)}^{{2}}}{{4}}+\frac{{\left({y}+{3}\right)}^{{2}}}{{9}}={1} and find the center, the major and minor axis, vertices, foci and ...

https://socratic.org/questions/how-do-you-graph-the-ellipse-x-2-2-4-y-3-2-9-1-and-find-the-center-the-major-and

Explanation given below Explanation: The given equation of ellipse: \displaystyle{\frac{{{\left({x}-{2}\right)}^{{2}}}}{{{4}}}}+{\frac{{{\left({y}+{3}\right)}^{{2}}}}{{{9}}}}={1} \displaystyle{\frac{{{\left({x}-{2}\right)}^{{2}}}}{{{2}^{{2}}}}}+{\frac{{{\left({y}+{3}\right)}^{{2}}}}{{{3}^{{2}}}}}={1} ...

How do I graph \displaystyle\frac{{\left({x}+{2}\right)}^{{2}}}{{9}}+\frac{{\left({y}-{1}\right)}^{{2}}}{{16}}={1} algebraically?

https://socratic.org/questions/how-do-i-graph-x-2-2-9-y-1-2-16-1-algebraically

MrsRudolph221 Apr 25, 2015 You have written about the graph of an ellipse. Since there is addition/subtraction happening with the x- and y-variables, you know that the shape is not centered ...

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