解決epsilon_{0}=1/4pik=8.85*10^-12C^2/N*m^2 |Microsoft數學求解器

評估 (復數求解)

ϵ_{0}=\frac{1}{4\pi k}\text{ and }\frac{1}{4\pi k}=\frac{177\left(Cm\right)^{2}}{20000000000000N}

解 ϵ_0

ϵ_{0}=\frac{177\left(Cm\right)^{2}}{20000000000000N}

k=\frac{5000000000000N}{177\pi \left(Cm\right)^{2}}\text{ and }m\neq 0\text{ and }C\neq 0\text{ and }N\neq 0

解 m

m=-\frac{1000000\sqrt{\frac{885N}{\pi k}}}{177|C|}

m=\frac{1000000\sqrt{\frac{885N}{\pi k}}}{177|C|}\text{, }\left(k=\frac{1}{4\pi ϵ_{0}}\text{ and }C\neq 0\text{ and }N>0\text{ and }ϵ_{0}>0\right)\text{ or }\left(k=\frac{1}{4\pi ϵ_{0}}\text{ and }C\neq 0\text{ and }ϵ_{0}<0\text{ and }N<0\right)

測驗

Algebra

5類似於:

\epsilon _ { 0 } = \frac { 1 } { 4 \pi k } = 8.85 \times 10 ^ { - 12 } C ^ { 2 } / N \cdot m ^ { 2 }

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