Giải d/dx(e^sqrt{1-x^2}*tanx)=

$$\frac { d } { d x } ( e ^ { \sqrt { 1 - x ^ { 2 } } } \cdot \tan x ) =$$

Tính giá trị

$$\frac{e^{\sqrt{1-x^{2}}}\left(-x\sin(2x)+2\sqrt{1-x^{2}}\right)}{2\sqrt{1-x^{2}}\left(\cos(x)\right)^{2}}$$

Lấy vi phân theo x

$$\frac{e^{\sqrt{1-x^{2}}}\left(-x^{5}\cos(x)\left(\sin(x)\right)^{2}-x^{5}\left(\cos(x)\right)^{3}-x^{5}\cos(x)+\sqrt{1-x^{2}}\sin(x)\left(x\cos(x)\right)^{2}-\sqrt{1-x^{2}}x^{4}\sin(x)\left(\cos(x)\right)^{2}+2\left(x\cos(x)\right)^{3}+\sin(x)\left(x\cos(x)\right)^{2}+2\sqrt{1-x^{2}}x^{4}\sin(x)+2x^{3}\cos(x)\left(\sin(x)\right)^{2}-x\cos(x)\left(\sin(x)\right)^{2}-x\left(\cos(x)\right)^{3}-4\sqrt{1-x^{2}}x^{2}\sin(x)-\sin(x)\left(\cos(x)\right)^{2}+2x^{3}\cos(x)-x\cos(x)+2\sqrt{1-x^{2}}\sin(x)\right)}{\left(1-x^{2}\right)^{\frac{5}{2}}\left(\cos(x)\right)^{3}}$$