Giải cos(sin3/9)=sin(-x^2+1)

$$\cos ( \frac { \sin 3 } { 9 } ) = \sin ( - x ^ { 2 } + 1 )$$

Tìm x (complex solution)

$$x=\left(-1\right)\left(1+i\ln(\frac{2499999987124027}{2500000000000000}i+\left(-\frac{11}{2500000000000000}\right)\times 532064998629829085151^{\frac{1}{2}})+\left(-2\right)\pi n_{1}\right)^{\frac{1}{2}}\text{, }n_{1}\in \mathrm{Z}$$

$$x=\left(1+i\ln(\frac{2499999987124027}{2500000000000000}i+\left(-\frac{11}{2500000000000000}\right)\times 532064998629829085151^{\frac{1}{2}})+\left(-2\right)\pi n_{1}\right)^{\frac{1}{2}}\text{, }n_{1}\in \mathrm{Z}$$

$$x=\left(-i\right)\left(-1+ArcTanI(\frac{2499999987124027}{5852714984928119936661}\times 532064998629829085151^{\frac{1}{2}})+2\pi n_{5}\right)^{\frac{1}{2}}\text{, }n_{5}\in \mathrm{Z}$$

$$x=i\left(-1+ArcTanI(\frac{2499999987124027}{5852714984928119936661}\times 532064998629829085151^{\frac{1}{2}})+2\pi n_{5}\right)^{\frac{1}{2}}\text{, }n_{5}\in \mathrm{Z}$$

Tìm x

$$x=-\sqrt{-2\pi n_{2}+\arcsin(0,9999999948496108)+1-\pi }\text{, }n_{2}\in \mathrm{Z}\text{, }n_{2}\leq -1$$

$$x=\sqrt{-2\pi n_{2}+\arcsin(0,9999999948496108)+1-\pi }\text{, }n_{2}\in \mathrm{Z}\text{, }n_{2}\leq -1$$

$$x=-\sqrt{-2\pi n_{1}+1-\arcsin(0,9999999948496108)}\text{, }n_{1}\in \mathrm{Z}\text{, }n_{1}\leq -1$$

$$x=\sqrt{-2\pi n_{1}+1-\arcsin(0,9999999948496108)}\text{, }n_{1}\in \mathrm{Z}\text{, }n_{1}\leq -1$$