2x^2geq50 eching

$$2x^2 \geq 50$$

x uchun yechish

$$x\in (-\infty,-5]\cup [5,\infty)$$

Yechim qadamlari

Ikki tarafini 2 ga bo‘ling. 2 >0 bo‘lganda, tengsizlikning yo‘nalishi o‘zgarmasdan qoladi.

$$x^{2}\geq \frac{50}{2}$$

25 ni olish uchun 50 ni 2 ga bo‘ling.

$$x^{2}\geq 25$$

25 ning kvadrat ildizini hisoblab, 5 natijaga ega bo‘ling. 25 ni 5^{2} sifatida qaytadan yozish.

$$x^{2}\geq 5^{2}$$

Tengsizlikda |x|\geq 5 bor.

$$|x|\geq 5$$

|x|\geq 5 ni x\leq -5\text{; }x\geq 5 sifatida qaytadan yozish.

$$x\leq -5\text{; }x\geq 5$$