z_{1}=(2+3i)(-1+2i);z_{2}=(1+3i)^2+(-4+5i)^2;z_{3}=(1-2i)^3:z_{4}=2/5+3ioperatorname{et}z_{5}=2+7i/-1-3i хәл итегез

$$z _ { 1 } = ( 2 + 3 i ) ( - 1 + 2 i ) ; z _ { 2 } = ( 1 + 3 i ) ^ { 2 } + ( - 4 + 5 i ) ^ { 2 } ; z _ { 3 } = ( 1 - 2 i ) ^ { 3 } : z _ { 4 } = \frac { 2 } { 5 + 3 i } \operatorname { et } z _ { 5 } = \frac { 2 + 7 i } { - 1 - 3 i }$$

z_1, z_2, z_3, z_4 өчен чишелеш

$$z_{1}=-8+i$$

$$z_{2}=-17-34i$$

$$z_{3}=\frac{-11+2i}{z_{4}}$$

$$z_{4}\in \mathrm{C}$$