y=6sinx/3-5sinx పరిష్కరించండి

$$y = \frac { 6 \sin x } { 3 - 5 \sin x }$$

yని పరిష్కరించండి (సంకీర్ణ పరిష్కారం)

$$y=\frac{6\sin(x)}{-5\sin(x)+3}$$

$$\nexists n_{2}\in \mathrm{Z}\text{ : }x=2\pi n_{2}+\arctan(\frac{3}{4})\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }x=2\pi n_{1}+\pi -\arctan(\frac{3}{4})$$

xని పరిష్కరించండి

$$x=arcSin(3\left(5y+6\right)^{-1}y)+2\pi n_{29}\text{, }n_{29}\in \mathrm{Z}\text{, }\nexists n_{2}\in \mathrm{Z}\text{ : }arcSin(3\left(5y+6\right)^{-1}y)+2\pi n_{29}=\pi +2\pi n_{2}+\left(-1\right)arcSin(\frac{3}{5})\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }arcSin(3\left(5y+6\right)^{-1}y)+2\pi n_{29}=arcSin(\frac{3}{5})+2\pi n_{1}$$

$$x=\pi +2\pi n_{30}+\left(-1\right)arcSin(3\left(5y+6\right)^{-1}y)\text{, }n_{30}\in \mathrm{Z}\text{, }\nexists n_{2}\in \mathrm{Z}\text{ : }\pi +2\pi n_{30}+\left(-1\right)arcSin(3\left(5y+6\right)^{-1}y)=\pi +2\pi n_{2}+\left(-1\right)arcSin(\frac{3}{5})\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }\pi +2\pi n_{30}+\left(-1\right)arcSin(3\left(5y+6\right)^{-1}y)=arcSin(\frac{3}{5})+2\pi n_{1}$$

yని పరిష్కరించండి

$$y=\frac{6\sin(x)}{-5\sin(x)+3}$$

$$\nexists n_{2}\in \mathrm{Z}\text{ : }x=2\pi n_{2}+\pi -\arcsin(\frac{3}{5})\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }x=2\pi n_{1}+\arcsin(\frac{3}{5})$$