{l}{sqrt{8}=sqrt{(a-3)^2+(-3)^2}}{b=sqrt{2}}{c=b}{text{Solvefor}dtext{where}}{d=c} పరిష్కరించండి

$$\left. \begin{array} { l } { \sqrt{8} = \sqrt{{(a - 3)} ^ {2} + {(-3)} ^ {2}} }\\ { b = \sqrt{2} }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

a, b, c, dని పరిష్కరించండి

$$a=3+i\text{, }b=\sqrt{2}\approx 1.414213562\text{, }c=\sqrt{2}\approx 1.414213562\text{, }d=\sqrt{2}\approx 1.414213562$$

$$a=3-i\text{, }b=\sqrt{2}\approx 1.414213562\text{, }c=\sqrt{2}\approx 1.414213562\text{, }d=\sqrt{2}\approx 1.414213562$$