Lös P=6+(5y-2)(3-t^4)

$$P = 6 + ( 5 y - 2 ) ( 3 - t ^ { 4 } )$$

Lös ut t (complex solution)

$$\left\{\begin{matrix}t=\sqrt{2}\left(-\frac{1}{2}+\frac{1}{2}i\right)\left(2-5y\right)^{-\frac{1}{4}}\sqrt[4]{15y-P}\text{; }t=\sqrt{2}\left(\frac{1}{2}+\frac{1}{2}i\right)\left(2-5y\right)^{-\frac{1}{4}}\sqrt[4]{15y-P}\text{; }t=\sqrt{2}\left(-\frac{1}{2}-\frac{1}{2}i\right)\left(2-5y\right)^{-\frac{1}{4}}\sqrt[4]{15y-P}\text{; }t=\sqrt{2}\left(\frac{1}{2}-\frac{1}{2}i\right)\left(2-5y\right)^{-\frac{1}{4}}\sqrt[4]{15y-P}\text{, }&y\neq \frac{2}{5}\\t\in \mathrm{C}\text{, }&P=6\text{ and }y=\frac{2}{5}\end{matrix}\right,$$

Lös ut P

$$P=2t^{4}+15y-5yt^{4}$$

Lös ut t

$$\left\{\begin{matrix}t=\sqrt[4]{-\frac{15y-P}{2-5y}}\text{; }t=-\sqrt[4]{-\frac{15y-P}{2-5y}}\text{, }&\left(y=\frac{P}{15}\text{ and }P\neq 6\right)\text{ or }\left(P=15y\text{ and }y\neq \frac{2}{5}\right)\text{ or }\left(y>\frac{2}{5}\text{ and }P\leq 15y\right)\text{ or }\left(P\geq 15y\text{ and }y<\frac{2}{5}\right)\\t\in \mathrm{R}\text{, }&P=6\text{ and }y=\frac{2}{5}\end{matrix}\right,$$