Zgjidh 4=1-x | Microsoft Math Solver

4 = 1 - x

Gjej x

x = - 3

Grafiku

Kuiz

Linear Equation

4 = 1 - x

Probleme të ngjashme nga kërkimi në ueb

Proof of continuity via Sequence Criterion?

https://math.stackexchange.com/questions/1031587/proof-of-continuity-via-sequence-criterion

In this case you do not need to split into two cases. Let

ϵ > 0

. Then as

s_{n} \to 1 / 2

, there is

N \in N

so that

∣ s_{n} - 1 / 2 ∣ < ϵ

whenever

n \geq N

. Now if

s_{n}

is ...

Operator or formal definition of mirroring the image of a function

https://math.stackexchange.com/questions/1880054/operator-or-formal-definition-of-mirroring-the-image-of-a-function

Well if you want

g

to be the reflection of

f

about the line

x = a

then you want

g (2 a - x) = f (x)

for every

x

in the domain of

f

, because the midpoint of

x

and

2 a - x

a

. To get a ...

Probability problem with bar graph

https://math.stackexchange.com/q/2505302

We may(?) assume that

h (x) = f (x) \cdot p

, where

p

is some (potentially crazy) polynomial. If you were not told that

f (x) = 2 - 2 x,

why would you assume that it is a rational function (the ratio of ...

Maximum value of the product of probabilities

https://math.stackexchange.com/questions/1384559/maximum-value-of-the-product-of-probabilities

Solution 1 is quiet understandable, but what I did not understood is the logic behind whole derivative part of the solution 2. The derivative of a curve at a point is equal to the gradient of the ...

Is this a geometric distribution [closed]

https://math.stackexchange.com/questions/2965421/is-this-a-geometric-distribution

Yes, in general, geometric distribution takes the form of

p (k) = (1 - p)^{k} p, k = 0, 1, 2 \dots,

Here

p = 1 - x

. Note that failure or success depends on the definition of the user.

Developing a polynomial.

https://math.stackexchange.com/questions/2763667/developing-a-polynomial

You must be careful as

w_{k}

depends of

k

and

n

. So in fact when you write

\prod_{k = 0}^{n} (1 - w_{k} X)

you mean:

\prod_{k = 0}^{n} (1 - e^{\frac{2 i k π}{n + 1}} X) = \prod_{k = 0}^{n - 1} (1 - e^{\frac{2 i k π}{n + 1}} X) (1 - e^{\frac{2 i n π}{n + 1}} X) \neq = \prod_{k = 0}^{n} (1 - e^{\frac{2 i k π}{n}} X) (1 - e^{\frac{2 i n π}{n + 1}} X)

...

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1-x=4

Ndërro anët në mënyrë që të gjitha kufizat me ndryshore të jenë në anën e majtë.

-x=4-1

Zbrit 1 nga të dyja anët.

-x=3

Zbrit 1 nga 4 për të marrë 3.

x=-3

Shumëzo të dyja anët me -1.

Shembuj

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[2534] [2 - 1 0135]

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x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}

Temat

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Probleme të ngjashme nga kërkimi në ueb

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