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2^{5}\times 3^{2}\times 5
Kviz
Algebra
5 težave, podobne naslednjim:
factor(1440)
Podobne težave pri spletnem iskanju
factor9.12
https://www.tiger-algebra.com/drill/factor9.12/
(912/100) Final result : 228 ——— = 9.12000 25 Reformatting the input : Changes made to your input should not affect the solution: (1): "9.12" was replaced by "(912/100)". Step by step solution : ...
findlcm.5,4,2
https://www.tiger-algebra.com/drill/findlcm.5,4,2/
Error - Decimal point not allowed here lcm(5,4,2) LCM(5,4,2) Least Common Multiple is : 20 Calculate Least Common Multiple for : 5, 4 and 2 Factorize of the ...
The number of ordered triples (a, b, c) of positive integers which satisfy the simultaneous equations ab + bc = 44, ac + bc = 33
https://math.stackexchange.com/q/664860
Your solution is correct. Noe that a=1,b-c=11 and a=11, b-c=1 both lead to a+b=12+c. Then 33=ac+bc=(12+c)c indeed has no solution. [There's an alomost-soution: c=-1 gives -33; so I wonder ...
Determinant using factor theorem
https://math.stackexchange.com/q/2660747
Your attempt is fine. And all the further explanations you need are already given by user348749 in How to solve this determinant I could just rephrase this here: Since for x+y+z=0, all three ...
Cannot find length of repeating block in decimal expansion for \frac{17}{78}
https://math.stackexchange.com/questions/802448/cannot-find-length-of-repeating-block-in-decimal-expansion-for-frac1778
Note that the period for a prime p is a factor of \varphi (p)=p-1 but need not be equal to it. This is because 10^{p-1} \equiv 1 \mod p. The period is the least n for which p|(10^n-1). If ...
Find the vertices of the polytope
https://math.stackexchange.com/questions/295533/find-the-vertices-of-the-polytope
Write the first constraint as \sum_j a_{1j} = m, with m < n ( I am just replacing the variable x by m). Since a_{i1}+a_{i2} = 1, and a_{ij}\geq 0, we see that this is equivalent to a_{i2} = 1-a_{i1} ...
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Podobne težave
factor(100)
factor(42)
factor(662)
factor(330)
factor(1440)
factor(7700)
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