Resolver (3+1/4)^2-2/3:1/4+sqrt[3]{1-19/27}=

$$( 3 + \frac { 1 } { 4 } ) ^ { 2 } - \frac { 2 } { 3 } : \frac { 1 } { 4 } + \sqrt[ 3 ] { 1 - \frac { 19 } { 27 } } =$$

Avaliar

$$\frac{137}{16}=8,5625$$

Passos Para a Resolução

Some 3 e \frac{1}{4} para obter \frac{13}{4}.

$$\left(\frac{13}{4}\right)^{2}-\frac{\frac{2}{3}}{\frac{1}{4}}+\sqrt[3]{1-\frac{19}{27}}$$

Calcule \frac{13}{4} elevado a 2 e obtenha \frac{169}{16}.

$$\frac{169}{16}-\frac{\frac{2}{3}}{\frac{1}{4}}+\sqrt[3]{1-\frac{19}{27}}$$

Divida \frac{2}{3} por \frac{1}{4} ao multiplicar \frac{2}{3} pelo recíproco de \frac{1}{4}.

$$\frac{169}{16}-\frac{2}{3}\times 4+\sqrt[3]{1-\frac{19}{27}}$$

Multiplique \frac{2}{3} e 4 para obter \frac{8}{3}.

$$\frac{169}{16}-\frac{8}{3}+\sqrt[3]{1-\frac{19}{27}}$$

Subtraia \frac{8}{3} de \frac{169}{16} para obter \frac{379}{48}.

$$\frac{379}{48}+\sqrt[3]{1-\frac{19}{27}}$$

Subtraia \frac{19}{27} de 1 para obter \frac{8}{27}.

$$\frac{379}{48}+\sqrt[3]{\frac{8}{27}}$$

Calcule \sqrt[3]{\frac{8}{27}} e obtenha \frac{2}{3}.

$$\frac{379}{48}+\frac{2}{3}$$

Some \frac{379}{48} e \frac{2}{3} para obter \frac{137}{16}.

$$\frac{137}{16}$$

Fatorizar

$$\frac{137}{2 ^ {4}} = 8\frac{9}{16} = 8,5625$$