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\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right)+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Utilize o teorema binomial \left(a-b\right)^{2}=a^{2}-2ab+b^{2} para expandir \left(\frac{1}{2}x-1\right)^{2}.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x\right)^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Considere \left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right). A multiplicação pode ser transformada na diferença dos quadrados através da regra: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Calcule o quadrado de 1.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}\right)^{2}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Expanda \left(\frac{1}{2}x\right)^{2}.
\frac{1}{4}x^{2}-x+1+\frac{1}{4}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Calcule \frac{1}{2} elevado a 2 e obtenha \frac{1}{4}.
\frac{1}{2}x^{2}-x+1-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Combine \frac{1}{4}x^{2} e \frac{1}{4}x^{2} para obter \frac{1}{2}x^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Subtraia 1 de 1 para obter 0.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x\right)^{2}-1
Considere \left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right). A multiplicação pode ser transformada na diferença dos quadrados através da regra: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Calcule o quadrado de 1.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}\right)^{2}x^{2}-1
Expanda \left(-\frac{1}{2}x\right)^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\frac{1}{4}x^{2}-1
Calcule -\frac{1}{2} elevado a 2 e obtenha \frac{1}{4}.
\frac{3}{4}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}-1
Combine \frac{1}{2}x^{2} e \frac{1}{4}x^{2} para obter \frac{3}{4}x^{2}.
\frac{3}{4}x^{2}-x+\frac{1}{4}x^{2}+x+1-1
Utilize o teorema binomial \left(a+b\right)^{2}=a^{2}+2ab+b^{2} para expandir \left(\frac{1}{2}x+1\right)^{2}.
x^{2}-x+x+1-1
Combine \frac{3}{4}x^{2} e \frac{1}{4}x^{2} para obter x^{2}.
x^{2}+1-1
Combine -x e x para obter 0.
x^{2}
Subtraia 1 de 1 para obter 0.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right)+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Utilize o teorema binomial \left(a-b\right)^{2}=a^{2}-2ab+b^{2} para expandir \left(\frac{1}{2}x-1\right)^{2}.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x\right)^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Considere \left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right). A multiplicação pode ser transformada na diferença dos quadrados através da regra: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Calcule o quadrado de 1.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}\right)^{2}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Expanda \left(\frac{1}{2}x\right)^{2}.
\frac{1}{4}x^{2}-x+1+\frac{1}{4}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Calcule \frac{1}{2} elevado a 2 e obtenha \frac{1}{4}.
\frac{1}{2}x^{2}-x+1-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Combine \frac{1}{4}x^{2} e \frac{1}{4}x^{2} para obter \frac{1}{2}x^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Subtraia 1 de 1 para obter 0.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x\right)^{2}-1
Considere \left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right). A multiplicação pode ser transformada na diferença dos quadrados através da regra: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Calcule o quadrado de 1.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}\right)^{2}x^{2}-1
Expanda \left(-\frac{1}{2}x\right)^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\frac{1}{4}x^{2}-1
Calcule -\frac{1}{2} elevado a 2 e obtenha \frac{1}{4}.
\frac{3}{4}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}-1
Combine \frac{1}{2}x^{2} e \frac{1}{4}x^{2} para obter \frac{3}{4}x^{2}.
\frac{3}{4}x^{2}-x+\frac{1}{4}x^{2}+x+1-1
Utilize o teorema binomial \left(a+b\right)^{2}=a^{2}+2ab+b^{2} para expandir \left(\frac{1}{2}x+1\right)^{2}.
x^{2}-x+x+1-1
Combine \frac{3}{4}x^{2} e \frac{1}{4}x^{2} para obter x^{2}.
x^{2}+1-1
Combine -x e x para obter 0.
x^{2}
Subtraia 1 de 1 para obter 0.