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\sqrt{\frac{4+5}{4}}+\frac{2\times 3+2}{3}\times \left(\frac{1\times 2+1}{2}\right)^{2}-\frac{3}{\frac{1\times 5+1}{5}}
Multiplique 1 e 4 para obter 4.
\sqrt{\frac{9}{4}}+\frac{2\times 3+2}{3}\times \left(\frac{1\times 2+1}{2}\right)^{2}-\frac{3}{\frac{1\times 5+1}{5}}
Some 4 e 5 para obter 9.
\frac{3}{2}+\frac{2\times 3+2}{3}\times \left(\frac{1\times 2+1}{2}\right)^{2}-\frac{3}{\frac{1\times 5+1}{5}}
Reescreva a raiz quadrada da divisão \frac{9}{4} à medida que a divisão de raízes quadradas \frac{\sqrt{9}}{\sqrt{4}}. Calcule a raiz quadrada do numerador e do denominador.
\frac{3}{2}+\frac{6+2}{3}\times \left(\frac{1\times 2+1}{2}\right)^{2}-\frac{3}{\frac{1\times 5+1}{5}}
Multiplique 2 e 3 para obter 6.
\frac{3}{2}+\frac{8}{3}\times \left(\frac{1\times 2+1}{2}\right)^{2}-\frac{3}{\frac{1\times 5+1}{5}}
Some 6 e 2 para obter 8.
\frac{3}{2}+\frac{8}{3}\times \left(\frac{2+1}{2}\right)^{2}-\frac{3}{\frac{1\times 5+1}{5}}
Multiplique 1 e 2 para obter 2.
\frac{3}{2}+\frac{8}{3}\times \left(\frac{3}{2}\right)^{2}-\frac{3}{\frac{1\times 5+1}{5}}
Some 2 e 1 para obter 3.
\frac{3}{2}+\frac{8}{3}\times \frac{9}{4}-\frac{3}{\frac{1\times 5+1}{5}}
Calcule \frac{3}{2} elevado a 2 e obtenha \frac{9}{4}.
\frac{3}{2}+6-\frac{3}{\frac{1\times 5+1}{5}}
Multiplique \frac{8}{3} e \frac{9}{4} para obter 6.
\frac{15}{2}-\frac{3}{\frac{1\times 5+1}{5}}
Some \frac{3}{2} e 6 para obter \frac{15}{2}.
\frac{15}{2}-\frac{3\times 5}{1\times 5+1}
Divida 3 por \frac{1\times 5+1}{5} ao multiplicar 3 pelo recíproco de \frac{1\times 5+1}{5}.
\frac{15}{2}-\frac{15}{1\times 5+1}
Multiplique 3 e 5 para obter 15.
\frac{15}{2}-\frac{15}{5+1}
Multiplique 1 e 5 para obter 5.
\frac{15}{2}-\frac{15}{6}
Some 5 e 1 para obter 6.
\frac{15}{2}-\frac{5}{2}
Reduza a fração \frac{15}{6} para os termos mais baixos ao retirar e anular 3.
5
Subtraia \frac{5}{2} de \frac{15}{2} para obter 5.