Resolver left(7-2right)^2*2+4/sqrt{64+3*4}div27/10

$$\frac{ { \left(7-2 \right) }^{ 2 } \times 2+4 }{ \sqrt{ 64 } +3 \times 4 } \div \frac{ 27 }{ 10 }$$

Avaliar

$$1$$

Passos Para a Resolução

Divida \frac{\left(7-2\right)^{2}\times 2+4}{\sqrt{64}+3\times 4} por \frac{27}{10} ao multiplicar \frac{\left(7-2\right)^{2}\times 2+4}{\sqrt{64}+3\times 4} pelo recíproco de \frac{27}{10}.

$$\frac{\left(\left(7-2\right)^{2}\times 2+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Subtraia 2 de 7 para obter 5.

$$\frac{\left(5^{2}\times 2+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Calcule 5 elevado a 2 e obtenha 25.

$$\frac{\left(25\times 2+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Multiplique 25 e 2 para obter 50.

$$\frac{\left(50+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Some 50 e 4 para obter 54.

$$\frac{54\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Multiplique 54 e 10 para obter 540.

$$\frac{540}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Calcule a raiz quadrada de 64 e obtenha 8.

$$\frac{540}{\left(8+3\times 4\right)\times 27}$$

Multiplique 3 e 4 para obter 12.

$$\frac{540}{\left(8+12\right)\times 27}$$

Some 8 e 12 para obter 20.

$$\frac{540}{20\times 27}$$

Multiplique 20 e 27 para obter 540.

$$\frac{540}{540}$$

Dividir 540 por 540 para obter 1.

$$1$$

Fatorizar

$$1$$