Resolver 3^-2*(frac{1/5)^-3*sqrt[3]{27}}{3-1/3-2*(-1/2+1)}=

$$\frac { 3 ^ { - 2 } \cdot ( \frac { 1 } { 5 } ) ^ { - 3 } \cdot \sqrt[ 3 ] { 27 } } { 3 - \frac { 1 } { 3 } - 2 \cdot ( - \frac { 1 } { 2 } + 1 ) } =$$

Avaliar

$$25$$

Passos Para a Resolução

Calcule 3 elevado a -2 e obtenha \frac{1}{9}.

$$\frac{\frac{1}{9}\times \left(\frac{1}{5}\right)^{-3}\sqrt[3]{27}}{3-\frac{1}{3}-2\left(-\frac{1}{2}+1\right)}$$

Calcule \frac{1}{5} elevado a -3 e obtenha 125.

$$\frac{\frac{1}{9}\times 125\sqrt[3]{27}}{3-\frac{1}{3}-2\left(-\frac{1}{2}+1\right)}$$

Multiplique \frac{1}{9} e 125 para obter \frac{125}{9}.

$$\frac{\frac{125}{9}\sqrt[3]{27}}{3-\frac{1}{3}-2\left(-\frac{1}{2}+1\right)}$$

Calcule \sqrt[3]{27} e obtenha 3.

$$\frac{\frac{125}{9}\times 3}{3-\frac{1}{3}-2\left(-\frac{1}{2}+1\right)}$$

Multiplique \frac{125}{9} e 3 para obter \frac{125}{3}.

$$\frac{\frac{125}{3}}{3-\frac{1}{3}-2\left(-\frac{1}{2}+1\right)}$$

Subtraia \frac{1}{3} de 3 para obter \frac{8}{3}.

$$\frac{\frac{125}{3}}{\frac{8}{3}-2\left(-\frac{1}{2}+1\right)}$$

Some -\frac{1}{2} e 1 para obter \frac{1}{2}.

$$\frac{\frac{125}{3}}{\frac{8}{3}-2\times \frac{1}{2}}$$

Multiplique 2 e \frac{1}{2} para obter 1.

$$\frac{\frac{125}{3}}{\frac{8}{3}-1}$$

Subtraia 1 de \frac{8}{3} para obter \frac{5}{3}.

$$\frac{\frac{125}{3}}{\frac{5}{3}}$$

Divida \frac{125}{3} por \frac{5}{3} ao multiplicar \frac{125}{3} pelo recíproco de \frac{5}{3}.

$$\frac{125}{3}\times \frac{3}{5}$$

Multiplique \frac{125}{3} e \frac{3}{5} para obter 25.

$$25$$

Fatorizar

$$5^{2}$$