{l}{sin(θ)-cos(θ)+1/sin(θ)+cos(θ)-1=1/sec(θ)-tan(θ)}{a=θ}{b=a}{text{Solvefor}ctext{where}}{c=b} କୁ ସମାଧାନ କରନ୍ତୁ

$$\left. \begin{array} { l } { \frac{\sin(\theta) - \cos(\theta) + 1}{\sin(\theta) + \cos(\theta) - 1} = \frac{1}{\sec(\theta) - \tan(\theta)} }\\ { a = \theta }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

θ, a, b, c ପାଇଁ ସମାଧାନ କରନ୍ତୁ

$$\theta =c$$

$$a=c$$

$$b=c$$

$$\nexists n_{2}\in \mathrm{Z}\text{ : }c=\pi n_{2}+\frac{\pi }{2}\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }c=2\pi n_{1}$$