Overslaan en naar de inhoud gaan
$\esthree{\exponential{a}{2} + 3 a b - \exponential{b}{2} = R}{c = (\exponential{a}{2} + \fraction{1}{2} a b) + (-\fraction{1}{4} a b + \fraction{1}{2} \exponential{b}{2}) + (-\fraction{1}{4} a b - \fraction{1}{5} \exponential{b}{2})}{d = c} $