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Solvi għal x
x=2\pi n_{1}+\frac{\pi }{2}
n_{1}\in \mathrm{Z}
Graff
Graff Żewġ Naħat f'2D
Graff f'2D
Kwizz
Trigonometry
\sin ( x ) = 1
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Solve \cos 2x - \sin x = 0 for 0 \le x \le 360
https://math.stackexchange.com/questions/1778416/solve-cos-2x-sin-x-0-for-0-le-x-le-360
From 2 \sin x=1, you should have \sin x=0.5. Sine is positive in the first two quadrants, you should obtain 30^{\circ} and 150^{\circ} as your solution as well.
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YOU are right. I cannot find any errors.
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Problemi Simili
\cos ( 3x + \pi ) = 0.5
\sin ( x ) = 1
\sin ( x ) - cos ( x ) = 0
\sin ( x ) + 2 = 3
{ \tan ( x ) } ^ {2} = 4
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