Issolvi y=(x-3)^2x_{1}

$$y = ( x - 3 ) ^ { 2 } x _ { 1 }$$

Solvi għal x_1 (complex solution)

$$\left\{\begin{matrix}x_{1}=\frac{y}{\left(x-3\right)^{2}}\text{, }&x\neq 3\\x_{1}\in \mathrm{C}\text{, }&y=0\text{ and }x=3\end{matrix}\right.$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(x-3\right)^{2}.

$$y=\left(x^{2}-6x+9\right)x_{1}$$

Uża l-propjetà distributtiva biex timmultiplika x^{2}-6x+9 b'x_{1}.

$$y=x^{2}x_{1}-6xx_{1}+9x_{1}$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$x^{2}x_{1}-6xx_{1}+9x_{1}=y$$

Ikkombina t-termini kollha li fihom x_{1}.

$$\left(x^{2}-6x+9\right)x_{1}=y$$

Iddividi ż-żewġ naħat b'x^{2}-6x+9.

$$\frac{\left(x^{2}-6x+9\right)x_{1}}{x^{2}-6x+9}=\frac{y}{x^{2}-6x+9}$$

Meta tiddividi b'x^{2}-6x+9 titneħħa l-multiplikazzjoni b'x^{2}-6x+9.

$$x_{1}=\frac{y}{x^{2}-6x+9}$$

Iddividi y b'x^{2}-6x+9.

$$x_{1}=\frac{y}{\left(x-3\right)^{2}}$$

Solvi għal x_1

$$\left\{\begin{matrix}x_{1}=\frac{y}{\left(x-3\right)^{2}}\text{, }&x\neq 3\\x_{1}\in \mathrm{R}\text{, }&y=0\text{ and }x=3\end{matrix}\right.$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(x-3\right)^{2}.

$$y=\left(x^{2}-6x+9\right)x_{1}$$

Uża l-propjetà distributtiva biex timmultiplika x^{2}-6x+9 b'x_{1}.

$$y=x^{2}x_{1}-6xx_{1}+9x_{1}$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$x^{2}x_{1}-6xx_{1}+9x_{1}=y$$

Ikkombina t-termini kollha li fihom x_{1}.

$$\left(x^{2}-6x+9\right)x_{1}=y$$

Iddividi ż-żewġ naħat b'x^{2}-6x+9.

$$\frac{\left(x^{2}-6x+9\right)x_{1}}{x^{2}-6x+9}=\frac{y}{x^{2}-6x+9}$$

Meta tiddividi b'x^{2}-6x+9 titneħħa l-multiplikazzjoni b'x^{2}-6x+9.

$$x_{1}=\frac{y}{x^{2}-6x+9}$$

Iddividi y b'x^{2}-6x+9.

$$x_{1}=\frac{y}{\left(x-3\right)^{2}}$$

Solvi għal x (complex solution)

$$\left\{\begin{matrix}x=3+x_{1}^{-\frac{1}{2}}\sqrt{y}\text{; }x=3-x_{1}^{-\frac{1}{2}}\sqrt{y}\text{, }&x_{1}\neq 0\\x\in \mathrm{C}\text{, }&y=0\text{ and }x_{1}=0\end{matrix}\right.$$

Solvi għal x

$$\left\{\begin{matrix}x=-\sqrt{\frac{y}{x_{1}}}+3\text{; }x=\sqrt{\frac{y}{x_{1}}}+3\text{, }&y\leq 0\text{ and }x_{1}<0\\x=-\sqrt{\frac{y}{x_{1}}}+3\text{; }x=\sqrt{\frac{y}{x_{1}}}+3\text{, }&y\geq 0\text{ and }x_{1}>0\\x\in \mathrm{R}\text{, }&y=0\text{ and }x_{1}=0\end{matrix}\right.$$